Aptitude - Numbers
Exercise : Numbers - General Questions
- Numbers - Formulas
- Numbers - General Questions
76.
A number when divide by 6 leaves a remainder 3. When the square of the number is divided by 6, the remainder is:
Answer: Option
Explanation:
Let x = 6q + 3.
Then, x2 = (6q + 3)2
= 36q2 + 36q + 9
= 6(6q2 + 6q + 1) + 3
Thus, when x2 is divided by 6, then remainder = 3.
77.
The sum of the two numbers is 12 and their product is 35. What is the sum of the reciprocals of these numbers ?
Answer: Option
Explanation:
Let the numbers be a and b. Then, a + b = 12 and ab = 35.
![]() |
a + b | = | 12 | ![]() |
![]() |
1 | + | 1 | ![]() |
= | 12 |
ab | 35 | b | a | 35 |
![]() |
12 |
35 |
78.
What will be remainder when 17200 is divided by 18 ?
Answer: Option
Explanation:
When n is even. (xn - an) is completely divisibly by (x + a)
(17200 - 1200) is completely divisible by (17 + 1), i.e., 18.
(17200 - 1) is completely divisible by 18.
On dividing 17200 by 18, we get 1 as remainder.
79.
If 1400 x x = 1050. Then, x = ?
Answer: Option
Explanation:
1400 x x = 1050 ![]() |
1050 | = | 3 |
1400 | 4 |
80.
(12 + 22 + 32 + ... + 102) = ?
Answer: Option
Explanation:
We know that (12 + 22 + 32 + ... + n2) = | 1 | n(n + 1)(2n + 1) |
6 |
Putting n = 10, required sum = | ![]() |
1 | x 10 x 11 x 21 | ![]() |
= 385 |
6 |
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