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Aptitude - Numbers - Discussion

Discussion Forum : Numbers - General Questions (Q.No. 76)
Numbers
76.
A number when divide by 6 leaves a remainder 3. When the square of the number is divided by 6, the remainder is:
0 
1
2
3
Answer: Option
Explanation:

Let x = 6q + 3.

Then, x2 = (6q + 3)2

   = 36q2 + 36q + 9

   = 6(6q2 + 6q + 1) + 3

Thus, when x2 is divided by 6, then remainder = 3.

Discussion:
11 comments Page 1 of 2.
Prasanna isane said:   3 years ago
As we know that, If a number or square of a number is divided by the same number, a remainder is same in both the conditions.
(1)
Ameena asma said:   7 years ago
As we know Dividend = Divisor * Quotient + Remainder.

D = (6*Q) + 3 -------> (1)
Its square root means D^2 = R -------> (2)
Substitute eqtn 1 into 2.
[(6*Q)+3]^2/6 = R
Take Q = 1.
Then, (6+3)^2/6 = R.
Therefore R = 3.
Manthan said:   7 years ago
@Rajveer it's not 9/6=3.

It's 9%6=3.
Pooja said:   7 years ago
It is (a+b)^2 formula = a^2 + b^2 + 2ab.
(36k^2+9+2*36k*9) How is simplify?

Please elaborate.
Pooja said:   7 years ago
How it is (a+b)^2 formula = a^2 + b^2 + 2ab?
Usir said:   8 years ago
The number is (6q+3).

Let q=1. we get 9. square of 9=81. If we divide 81 by 6 we will get remainder 3.
Rajveer said:   9 years ago
@Sayali.
How you get 9/6 =3?
Sayali said:   10 years ago
Easiest way we can do is:

Which applicable to sum no 31, 41.

Square of 1st sum remainder is 9. So 9/6=3.

Answer is 3.
Supriya said:   1 decade ago
@Mona, it is (a+b)^2 formula = a^2 + b^2 + 2ab.
Haresh said:   1 decade ago
6+3=9 81/6 is remainder 3.
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