Aptitude - Numbers - Discussion

Discussion Forum : Numbers - General Questions (Q.No. 78)
78.
What will be remainder when 17200 is divided by 18 ?
17
16
1
2
Answer: Option
Explanation:

When n is even. (xn - an) is completely divisibly by (x + a)

(17200 - 1200) is completely divisible by (17 + 1), i.e., 18.

   (17200 - 1) is completely divisible by 18.

   On dividing 17200 by 18, we get 1 as remainder.

Discussion:
27 comments Page 2 of 3.

Gopi said:   7 years ago
17^200 - 1 = 18 * quotient.
So,
17^200 = 18 * quotient + 1.

We have taken that 1 as a reminder in all type of problems.

So, ans = 1.

Rounak said:   7 years ago
What to do when n is odd number?

Manoranjan sahoo said:   7 years ago
(17^199+17)/18,
(17^199+1)/18 is completely divisible,
and the reminder is 16.

Bhavesh sharma said:   8 years ago
I have more simple solution:
17^2 divided by 1 then the remainder is 1.
So we can write 17^200 as( 17^2)^100.
So we get 1 remainder.

Shubham said:   8 years ago
Can somebody give all the division rules for term (x^n - a^n).

ESRAK AHMED KAFI said:   9 years ago
x^n -1 is divisible by (X+1) when n is even. so, when we will divide X^n by (X+1) the remainder will be definitely 1.

Example: 2^2 =4, when 4 is divided by (2+1) i.e. 3, then the remainder will be 1.

Sweety said:   9 years ago
Please, anyone explain this clearly.

Dev said:   9 years ago
Please give me solution for finding the value of R. And explain the answer.

26^57÷29 = R.
128^100÷153 = R.
2^187÷51 = R.
17^14÷72 = R.

Mir Rokon Uddin said:   9 years ago
It is notable that the power of 17 is even.

So we can consider 17^2 and divide it by 18. And we got 1 as a reminder. So the answer is 1.

Bharath said:   9 years ago
17^200 = (18 - 1)^200 gives (18^200) - 2 * 18 + 1 which give remainder 1 when divided by 18.


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