Aptitude - Logarithm - Discussion
Discussion Forum : Logarithm - General Questions (Q.No. 12)
12.
If logx | ![]() |
9 | ![]() |
= - | 1 | , then x is equal to: |
16 | 2 |
Answer: Option
Explanation:
logx | ![]() |
9 | ![]() |
= - | 1 |
16 | 2 |
![]() |
= | 9 |
16 |
![]() |
1 | = | 9 |
x | 16 |
![]() |
16 |
9 |
![]() |
![]() |
16 | ![]() |
2 |
9 |
![]() |
256 |
81 |
Discussion:
17 comments Page 2 of 2.
Hemant said:
9 years ago
Your explanation is too good @@Rohit.
Rushikesh said:
9 years ago
@ Mounika.
X = 2.15.
X = 2.15.
Himansu said:
8 years ago
log(0.1)=-1/3.
Multiplying LHS and RHS by -3 we get,
RHS = 1 and,
LHS = -3 logx(1/10),
= logx (10) to power 3,
= logx (1000)=1,
x = 1000.
Multiplying LHS and RHS by -3 we get,
RHS = 1 and,
LHS = -3 logx(1/10),
= logx (10) to power 3,
= logx (1000)=1,
x = 1000.
Xcpen said:
7 years ago
X^-1/2 = 9/16,
1/x^1/2 = 9/16,
1/x^1/2 = (3/4)^1/2,
1/x = 3/4,
X = 4/3.
1/x^1/2 = 9/16,
1/x^1/2 = (3/4)^1/2,
1/x = 3/4,
X = 4/3.
Nagaraju Azmeera said:
5 years ago
Thanks for explaining @Pavitra.
Deepanesh said:
5 years ago
Log X = m.
X = 9/16.
m = -1/2,
a power m = X ->Formula.
X = 9/16.
m = -1/2,
a power m = X ->Formula.
J. Bhargav sai said:
4 years ago
This is also correct answer.
Log x (9/16) = -1/2,
Log x (3/4)^2 = -1/2,
Log x^ (-1/2) = (3/4) ^2,
√x = (3/4) ^2.
Root and square both cancel.
And after x = (3/4).
X = (3/4),
Log x (9/16) = -1/2,
Log x (3/4)^2 = -1/2,
Log x^ (-1/2) = (3/4) ^2,
√x = (3/4) ^2.
Root and square both cancel.
And after x = (3/4).
X = (3/4),
(2)
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