Aptitude - Logarithm - Discussion
Discussion Forum : Logarithm - General Questions (Q.No. 15)
15.
The value of log2 16 is:
Answer: Option
Explanation:
Let log2 16 = n.
Then, 2n = 16 = 24 
n = 4.
log2 16 = 4.
Discussion:
12 comments Page 1 of 2.
Hariharan - Hark said:
1 decade ago
Simple answer would be :
16 can be written as 2 to the power 4.
16 -> (2^4) which can be written as (4 log 2).
Now log 16 to base 2 is written as 4 log 2 to the base 2.
log 2 to the base 2 is 1.
So Answer is 4x1 = 4.
16 can be written as 2 to the power 4.
16 -> (2^4) which can be written as (4 log 2).
Now log 16 to base 2 is written as 4 log 2 to the base 2.
log 2 to the base 2 is 1.
So Answer is 4x1 = 4.
Shubhro said:
8 years ago
The log16 to the base of 2 = log 2^4 to the base of 2 = 4log2 to the base of 2 = 4*log2 to the base of 2 = 4 * 1 = 4.
That, will be the simplest guys and I agree @Hariharan.
That, will be the simplest guys and I agree @Hariharan.
(2)
Sravani said:
5 years ago
= log2^(16).
= log2^(8*2).
= log2^(8)+log2^(2)// logx^(x)=1.
= log2^(2^(3))+1.
= 3 log2^(2)+1.
= 3* 1+1.
= 3+1.
= 4.
= log2^(8*2).
= log2^(8)+log2^(2)// logx^(x)=1.
= log2^(2^(3))+1.
= 3 log2^(2)+1.
= 3* 1+1.
= 3+1.
= 4.
Narendra said:
5 years ago
= log2^(16).=log2^(8*2).
= log2^(8)+log2^(2)//lgx^(x) = 1.
= log2^(2^(3)) + 1.
= 3log2^(2) + 1.
= 3 * 1 + 1.
= 3 + 1= 4.
= log2^(8)+log2^(2)//lgx^(x) = 1.
= log2^(2^(3)) + 1.
= 3log2^(2) + 1.
= 3 * 1 + 1.
= 3 + 1= 4.
Prakash said:
1 decade ago
Let us take log16/log2.
= 4log2/log2.
= 4.
This is the answer "4"
= 4log2/log2.
= 4.
This is the answer "4"
PARMOD said:
1 decade ago
This sum can be solved by this method:-
EXPLANATION:-
LOG16/LOG2
LOG(2)4/LOG2
4LOG2/LOG2=4
EXPLANATION:-
LOG16/LOG2
LOG(2)4/LOG2
4LOG2/LOG2=4
Jithendra said:
7 years ago
= log2 16.
= log2 2*2*2*2,
= log2 2 + log2 2 + log2 2 + log2 2,
= 1+1+1+1,
= 4.
= log2 2*2*2*2,
= log2 2 + log2 2 + log2 2 + log2 2,
= 1+1+1+1,
= 4.
Subham said:
6 years ago
= log2 16.
= log2 2*2*2*2,
= log2 2 + log2 2 + log2 2 + log2 2,
= 1+1+1+1,
= 4.
= log2 2*2*2*2,
= log2 2 + log2 2 + log2 2 + log2 2,
= 1+1+1+1,
= 4.
(1)
Niket said:
5 years ago
Given:log 2 (16).
=log 2(4)^2
=2log2(4)
=2log2(2)^2
=4log2(2)
=4(1)
= 4.
=log 2(4)^2
=2log2(4)
=2log2(2)^2
=4log2(2)
=4(1)
= 4.
(2)
Suyash said:
8 years ago
log2 16 ;
log2 2^4;
4 log2^2 (bcz loga a=1),
So, 4.
log2 2^4;
4 log2^2 (bcz loga a=1),
So, 4.
(1)
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