Aptitude - Height and Distance - Discussion

Discussion Forum : Height and Distance - General Questions (Q.No. 6)
6.
The angle of elevation of the sun, when the length of the shadow of a tree 3 times the height of the tree, is:
30°
45°
60°
90°
Answer: Option
Explanation:

Let AB be the tree and AC be its shadow.

Let ACB = .

Then, AC = 3         cot = 3
AB

= 30°.

Discussion:
62 comments Page 4 of 7.

Sajid said:   8 years ago
Why can't we say tan 60?

Shaik sajid said:   8 years ago
Hey answer is cot 30 degrees but we can also say tan 60 degrees.

Because in the options 60 also there.

Mahesh said:   8 years ago
Why cot or tan, why don't we take sine or cosine?

Mahendra said:   8 years ago
Let height of the shadow = x.
Then the shadow of the is root3 times the height of the tree = root3*x.
Nnow tan θ =x/root3*x.
x,x gets cancel and 1/3 remains.
we know the tan1/3 = 30°.

Sangeethasendhil. said:   8 years ago
Cot θ = root 3.

Then θ =30°; I can't understand this step, can anyone this calculation?

Aadil said:   8 years ago
Angle = Tan inverse of( Opposite side/ Adjacent side).
So, the Final answer is 30 deg. As tan inverse of 1/root3.

Madhav said:   9 years ago
Tan60 = 1/3.

Vinay said:   9 years ago
Can anyone explain me taking of angle ACB and why not ABC?

Am thinking the eye of the sun for elevation is from b.

Kshyama Sagar said:   9 years ago
Considering the above Fig.

Assume that the angle of elevation made by the Sun in the shadow of tree is < acb= θ and height of tree (AB) is = x (in meter).

According to question,
shadow of the tree is √3 times the height of the tree.
shadow of a tree(CA) will be = √3x.
tan θ = AB/AC = x/√3x.
tan θ =1/√3.
tan θ = tan 1/√3.
tan θ = tan30°.
θ = 30° (Require answer).

Tharun said:   9 years ago
Cot 30 = tan 60.


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