Aptitude - Height and Distance - Discussion
Discussion Forum : Height and Distance - General Questions (Q.No. 6)
6.
The angle of elevation of the sun, when the length of the shadow of a tree 3 times the height of the tree, is:
Answer: Option
Explanation:
Let AB be the tree and AC be its shadow.
Let 
ACB = 
.
| Then, | AC | = | 3  cot = 3 |
| AB |
= 30°.
Discussion:
62 comments Page 3 of 7.
Prashanth said:
7 years ago
This can be tan 60 also right, because the value of tan 60 is √3.
Sandeep sai kumar said:
7 years ago
We consider;
ab=x then,
ca=√3x,
So tanθ=opposite/adjacent.
Tanθ=ab/ac.
Tanθ=x/√3x,
Tanθ=1/√3,
θ=tanθ 1(1/√3),
θ=tan (√3),
θ=30°.
ab=x then,
ca=√3x,
So tanθ=opposite/adjacent.
Tanθ=ab/ac.
Tanθ=x/√3x,
Tanθ=1/√3,
θ=tanθ 1(1/√3),
θ=tan (√3),
θ=30°.
Dattatray said:
7 years ago
Let x be the height of tree and shadow length √3 x,
Tanθ= x &div √3 x.
θ=tan-1(1 &div √3),
θ=30.
Tanθ= x &div √3 x.
θ=tan-1(1 &div √3),
θ=30.
Swapnali wadhavne said:
7 years ago
Here shadow is √3 times the tree height.
Therefore AC=√3AB.
NOW tanθ =AB/AC,
tanθ =AB/√3AB,
tanθ=1/√3,
θ=tan^-1((1/√3)),
θ=30°.
Therefore AC=√3AB.
NOW tanθ =AB/AC,
tanθ =AB/√3AB,
tanθ=1/√3,
θ=tan^-1((1/√3)),
θ=30°.
Akhila V U said:
7 years ago
Cot θ= AC/AB.
Cot θ =(3 * AB)/AB,
Cot θ= 3.
Therefore :
θ = 30.
Cot θ =(3 * AB)/AB,
Cot θ= 3.
Therefore :
θ = 30.
Biplab Gorai said:
7 years ago
Thanks for the given solution.
Kelzhenry said:
7 years ago
AB/AC = Tanθ.
From the question,
AB/√3AB =Tanθ
1/√3 = Tanθ
θ = 30°.
From the question,
AB/√3AB =Tanθ
1/√3 = Tanθ
θ = 30°.
Amul said:
7 years ago
How can say that cot 30°? tan 60 is not compatitable at all I think sin60 or cos60 would be right choice.
Aniket said:
8 years ago
We can also take tan instead of cot.
Sivaji said:
8 years ago
How to take a cotθ formula?
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