Aptitude - Height and Distance - Discussion
Discussion Forum : Height and Distance - General Questions (Q.No. 6)
6.
The angle of elevation of the sun, when the length of the shadow of a tree 3 times the height of the tree, is:
Answer: Option
Explanation:
Let AB be the tree and AC be its shadow.
Let 
ACB = 
.
| Then, | AC | = | 3  cot = 3 |
| AB |
= 30°.
Discussion:
63 comments Page 7 of 7.
Balaji said:
2 decades ago
Let me explain here, here carefully,
Here in the problem tree is taken as perpendicular i.e. AB and they also informed that the shadow of tree 3 times the tree i.e. 3 AB. Here shadow is nothing but base.
So we have formula that cot thita = cos θ/ sin θ
Cot θ= AC/AB
= 3 * AB/AB
Cot θ= 3
Cot θ= Cot 30
θ = 30
Here in the problem tree is taken as perpendicular i.e. AB and they also informed that the shadow of tree 3 times the tree i.e. 3 AB. Here shadow is nothing but base.
So we have formula that cot thita = cos θ/ sin θ
Cot θ= AC/AB
= 3 * AB/AB
Cot θ= 3
Cot θ= Cot 30
θ = 30
Kapil said:
2 decades ago
Angle ACB = Angle BCA
There are different ways to do same question.
they are using cot @ =AC/BC
but you can also use tan @ = perpendicular/base = AB/AC
There are different ways to do same question.
they are using cot @ =AC/BC
but you can also use tan @ = perpendicular/base = AB/AC
Idiotshere said:
2 decades ago
Help me please!.
I'm not getting here why we are saying ACB why don't BCA ?
And another is that why AC/AB why don't AB/AC = tan60 ?
I'm not getting here why we are saying ACB why don't BCA ?
And another is that why AC/AB why don't AB/AC = tan60 ?
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