Aptitude - Height and Distance - Discussion
Discussion Forum : Height and Distance - General Questions (Q.No. 6)
6.
The angle of elevation of the sun, when the length of the shadow of a tree 3 times the height of the tree, is:
Answer: Option
Explanation:
Let AB be the tree and AC be its shadow.
Let 
ACB = 
.
| Then, | AC | = | 3  cot = 3 |
| AB |
= 30°.
Discussion:
62 comments Page 6 of 7.
Maddy said:
1 decade ago
Since you know that tan @ = P/B that is AB/AC. And the opposite of tan @ is cot@= B/P that is AC/AB.
I hope it will help you to understand.
I hope it will help you to understand.
Dendup said:
1 decade ago
may i know how AC/AB is related to cot@??
Shro said:
1 decade ago
Thanks Balaji
Kanaga said:
1 decade ago
@Mjp:Thanks!!!
Mjp said:
1 decade ago
The sun forms a angle of depression. So as the sun is very far away it is hard to take the value, so we can take the angle of elevation of a tree which is equal to the angle of depression.
Baribie said:
1 decade ago
Can any one explain the question?
Kanaga said:
1 decade ago
Hi,
I am not getting the question correctly. They have asked about the angle of elevation of sun. Why should we go for angle of elevation of tree?
I am not getting the question correctly. They have asked about the angle of elevation of sun. Why should we go for angle of elevation of tree?
Anchal said:
1 decade ago
We can also solve like this...let AB=x, then AC=3x, Now
AB/AC=tanθ
then x/3=tanθ
After crossing x from x..we get
1/3=tanθ
so tan 30=1/3
so θ=30...Ans..
AB/AC=tanθ
then x/3=tanθ
After crossing x from x..we get
1/3=tanθ
so tan 30=1/3
so θ=30...Ans..
Appu said:
1 decade ago
Thank you Balaji.
Balaji said:
1 decade ago
Let me explain here, here carefully,
Here in the problem tree is taken as perpendicular i.e. AB and they also informed that the shadow of tree 3 times the tree i.e. 3 AB. Here shadow is nothing but base.
So we have formula that cot thita = cos θ/ sin θ
Cot θ= AC/AB
= 3 * AB/AB
Cot θ= 3
Cot θ= Cot 30
θ = 30
Here in the problem tree is taken as perpendicular i.e. AB and they also informed that the shadow of tree 3 times the tree i.e. 3 AB. Here shadow is nothing but base.
So we have formula that cot thita = cos θ/ sin θ
Cot θ= AC/AB
= 3 * AB/AB
Cot θ= 3
Cot θ= Cot 30
θ = 30
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