Aptitude - Height and Distance - Discussion
Discussion Forum : Height and Distance - General Questions (Q.No. 6)
6.
The angle of elevation of the sun, when the length of the shadow of a tree 3 times the height of the tree, is:
Answer: Option
Explanation:
Let AB be the tree and AC be its shadow.
Let 
ACB = 
.
| Then, | AC | = | 3  cot = 3 |
| AB |
= 30°.
Discussion:
62 comments Page 1 of 7.
Siddharth said:
3 weeks ago
The length of the tree = AB, shadow of tree = CB.
Assume AB = x then CB = √3x.
Now , tanθ = AB / CB = x/√3x = 1/√3.
we know tan30° = 1/√3.
So, θ = 30°
Assume AB = x then CB = √3x.
Now , tanθ = AB / CB = x/√3x = 1/√3.
we know tan30° = 1/√3.
So, θ = 30°
(1)
ATWONGYEIRE NELBERT said:
3 months ago
Thanks all for explaining the answer.
(1)
Jabbar jr said:
2 years ago
The length of the shadow fo the tree is √3.
Here we want length of the tree only, So;
tanθ=opp/adj.
tanθ = x/√3.
θ=x/√3 => θ=1/√3.
So, the answer is θ = 30°.
Here we want length of the tree only, So;
tanθ=opp/adj.
tanθ = x/√3.
θ=x/√3 => θ=1/√3.
So, the answer is θ = 30°.
(12)
Shaik Nayab said:
3 years ago
Consider <ABC,
Height of the tree taken as = h.
Given, length of the shadow of a tree √3 times the height of the tree = √3 h.
I have taken, tan θ = BC/AC.
= h/√3 h.
=> numerator and denominator " h" canceled;
Remaining = 1/√3.
So, tan θ = 1 /√3 (Given data on both sides, opposite and adjacent sides, so I can take tan).
Then, θ = 30°.
Height of the tree taken as = h.
Given, length of the shadow of a tree √3 times the height of the tree = √3 h.
I have taken, tan θ = BC/AC.
= h/√3 h.
=> numerator and denominator " h" canceled;
Remaining = 1/√3.
So, tan θ = 1 /√3 (Given data on both sides, opposite and adjacent sides, so I can take tan).
Then, θ = 30°.
(13)
Nicholas Hatontola said:
3 years ago
Why are we considering BC as the length of the shadow instead of AC? Isn't the shadow supposed to be the base?
Please explain me.
Please explain me.
(1)
Vivek Sunny said:
4 years ago
@Aditya.
We can choose any ratio either tan or cot.
But, which relates both adjacent and height.
We can choose any ratio either tan or cot.
But, which relates both adjacent and height.
Gurpreet said:
4 years ago
Thanks all.
(1)
Aditya said:
5 years ago
Why cot is taken here. Why we cannot take tan? Please explain me.
(2)
Aditi said:
5 years ago
Here we are taking base AC as a shadow of height then we can solve it like;
Given-
Shadow of a tree is √3 times the height of the tree.
Height = √3AB.
3AB/AC.
3 = AC/AB.
tan = 1/cot.
tan = Perpendicular/Base so the inverse of tan is cot.
Cot = AC/AB (Base/Perpendicular).
Cot 3 = 30°.
Given-
Shadow of a tree is √3 times the height of the tree.
Height = √3AB.
3AB/AC.
3 = AC/AB.
tan = 1/cot.
tan = Perpendicular/Base so the inverse of tan is cot.
Cot = AC/AB (Base/Perpendicular).
Cot 3 = 30°.
(2)
Shruti jalkote said:
5 years ago
Thanks all.
(1)
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