Aptitude - Compound Interest - Discussion

Discussion Forum : Compound Interest - General Questions (Q.No. 2)
2.
The difference between simple and compound interests compounded annually on a certain sum of money for 2 years at 4% per annum is Re. 1. The sum (in Rs.) is:
625
630
640
650
Answer: Option
Explanation:

Let the sum be Rs. x. Then,

C.I. = x 1 + 4 2 - x = 676 x - x = 51 x.
100 625 625

S.I. = x x 4 x 2 = 2x .
100 25

51x - 2x = 1
625 25

x = 625.

Discussion:
149 comments Page 8 of 15.

Eshwar said:   10 years ago
CI = A-P.

A = P(1+r/100)n.

CI = P(1+r/100)n-P.

Where in above problem P = x.

$weth@ said:   10 years ago
Is that a formula you used over there?

[x(1+4/100)2]-x? where and all we can use this?

Manaswini said:   10 years ago
I can't understand this please some one help me to understand this sum.

Salman said:   10 years ago
Actually the question is wrong:

It should be difference between compound and simple interest.

Since compound interest will always be larger than simple interest given the same rate and period.

Sagy said:   10 years ago
I did not understand this sum please help give me a simple way to solve this sum.

Santhosh P said:   10 years ago
Difference for 2 years = P*(R/100)^2.

=> P*(4/100)^2 = 1.

=> P = 625.

Anu said:   10 years ago
Krishna please solve last equation also.

Priya said:   10 years ago
Should we take x as principle? Or we can take any other variable like P?

Princess said:   9 years ago
Can anyone tell me how can we find the sum and rate when compound interest for two successive years are are given?

Amit said:   9 years ago
Principal for two years = pr2/100*100.

Three years = pr2(300+r)/100*100*100.


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