Aptitude - Compound Interest - Discussion

Discussion Forum : Compound Interest - General Questions (Q.No. 2)
2.
The difference between simple and compound interests compounded annually on a certain sum of money for 2 years at 4% per annum is Re. 1. The sum (in Rs.) is:
625
630
640
650
Answer: Option
Explanation:

Let the sum be Rs. x. Then,

C.I. = x 1 + 4 2 - x = 676 x - x = 51 x.
100 625 625

S.I. = x x 4 x 2 = 2x .
100 25

51x - 2x = 1
625 25

x = 625.

Discussion:
149 comments Page 15 of 15.

Gourikrishna said:   6 years ago
Explain clearly the first step.

Bhavani said:   6 years ago
S.P - C.I = 1.

p = 1 (100/4)^2.
= 1(100 x 100/4 x 4).
= 25 x 25.
= 625.

Bhavani said:   6 years ago
Principal = X say.

C.I = Amount-Principal.
= {X[1+4/100]^2-X}.

S.I = [ X(4)(2)/100].

Yogesh patil said:   6 years ago
One of the simplest way to solve difference between si and ci by using simple formula
Diff=PR^2/100^2.
Diff=1*4^2/100*100.
Diff=1/625.
Ans=625.

Yogesh patil said:   6 years ago
One of the simplest way to solve difference between si and ci by using simple formula
Diff=PR^2/100^2.
Diff=1*4^2/100*100.
Diff=1/625.
Ans=625.

Anju Chimouriya said:   6 years ago
Why cannot we use the compound interest formula in this problem?

Mithra said:   5 years ago
Excellent. Thanks all for explaining.

Naveen said:   4 years ago
1=10000*x/4 * 4.
= 625.

Anushka Chouhan said:   5 months ago
Here, use a simple formula for the difference of 2 years = (pr) ^ 2/10000.


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