Aptitude - Compound Interest - Discussion
Discussion Forum : Compound Interest - General Questions (Q.No. 2)
2.
The difference between simple and compound interests compounded annually on a certain sum of money for 2 years at 4% per annum is Re. 1. The sum (in Rs.) is:
Answer: Option
Explanation:
Let the sum be Rs. x. Then,
C.I. = | ![]() |
x | ![]() |
1 + | 4 | ![]() |
2 | - x | ![]() |
= | ![]() |
676 | x | - x | ![]() |
= | 51 | x. |
100 | 625 | 625 |
S.I. = | ![]() |
x x 4 x 2 | ![]() |
= | 2x | . |
100 | 25 |
![]() |
51x | - | 2x | = 1 |
625 | 25 |
x = 625.
Discussion:
149 comments Page 15 of 15.
Gourikrishna said:
6 years ago
Explain clearly the first step.
Bhavani said:
6 years ago
S.P - C.I = 1.
p = 1 (100/4)^2.
= 1(100 x 100/4 x 4).
= 25 x 25.
= 625.
p = 1 (100/4)^2.
= 1(100 x 100/4 x 4).
= 25 x 25.
= 625.
Bhavani said:
6 years ago
Principal = X say.
C.I = Amount-Principal.
= {X[1+4/100]^2-X}.
S.I = [ X(4)(2)/100].
C.I = Amount-Principal.
= {X[1+4/100]^2-X}.
S.I = [ X(4)(2)/100].
Yogesh patil said:
6 years ago
One of the simplest way to solve difference between si and ci by using simple formula
Diff=PR^2/100^2.
Diff=1*4^2/100*100.
Diff=1/625.
Ans=625.
Diff=PR^2/100^2.
Diff=1*4^2/100*100.
Diff=1/625.
Ans=625.
Yogesh patil said:
6 years ago
One of the simplest way to solve difference between si and ci by using simple formula
Diff=PR^2/100^2.
Diff=1*4^2/100*100.
Diff=1/625.
Ans=625.
Diff=PR^2/100^2.
Diff=1*4^2/100*100.
Diff=1/625.
Ans=625.
Anju Chimouriya said:
6 years ago
Why cannot we use the compound interest formula in this problem?
Mithra said:
5 years ago
Excellent. Thanks all for explaining.
Naveen said:
4 years ago
1=10000*x/4 * 4.
= 625.
= 625.
Anushka Chouhan said:
5 months ago
Here, use a simple formula for the difference of 2 years = (pr) ^ 2/10000.
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