Aptitude - Compound Interest - Discussion
Discussion Forum : Compound Interest - General Questions (Q.No. 2)
2.
The difference between simple and compound interests compounded annually on a certain sum of money for 2 years at 4% per annum is Re. 1. The sum (in Rs.) is:
Answer: Option
Explanation:
Let the sum be Rs. x. Then,
| C.I. = |  |
x |  |
1 + | 4 |  |
2 | - x |  |
= | |
676 | x | - x | |
= | 51 | x. |
| 100 | 625 | 625 |
| S.I. = | |
x x 4 x 2 | |
= | 2x | . |
| 100 | 25 |
 |
51x | - | 2x | = 1 |
| 625 | 25 |
x = 625.
Discussion:
149 comments Page 7 of 15.
An aspirant said:
1 decade ago
Sum = Difference*(100) square/(r)square.
Prabhjot Singh said:
1 decade ago
Just equate:
CI-SI = P(R/100)(R/100) for 2 years.
CI-SI = P(R/100)(R/100)(300+R/100) for 3 years.
By these formula's it is easier to calculate the result.
CI-SI = P(R/100)(R/100) for 2 years.
CI-SI = P(R/100)(R/100)(300+R/100) for 3 years.
By these formula's it is easier to calculate the result.
Raja said:
1 decade ago
What is the shortcut formula to find differences of ci and si for 4 years and 5 years?
Siva said:
1 decade ago
Difference between 2 years = pr^2/100^2.
Ganga said:
1 decade ago
@Pankaj parashar.
Please tell me how CI rate for 2 years = 8.16%.
Please help me.
Please tell me how CI rate for 2 years = 8.16%.
Please help me.
Aparna said:
1 decade ago
P(1+0.04)^2-P)-P*0.08.
From the above step how did you got that P(1/625) = 1.
Can you please explain me?
From the above step how did you got that P(1/625) = 1.
Can you please explain me?
Hema said:
1 decade ago
Shortcut formula P = (100/R)^T*D, D = Difference here.
= (100/4)^2*1 = 625.
= (100/4)^2*1 = 625.
Bhupathi raju said:
1 decade ago
Any easiest method solve this problem?
Monalisa said:
1 decade ago
Hey guys, I have a shortcut formula for such problem:
p = d*100^2/r^2 (only for 2 yrs).
Where p = principle.
d = difference.
r = rate.
p = d*100^2/r^2 (only for 2 yrs).
Where p = principle.
d = difference.
r = rate.
Rick said:
1 decade ago
You people should add the formula of C.I in the formula section which is missing.
C.I = p[(1+r/100)^n -1].
C.I = p[(1+r/100)^n -1].
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