Aptitude - Compound Interest - Discussion
Discussion Forum : Compound Interest - General Questions (Q.No. 13)
13.
The difference between simple interest and compound on Rs. 1200 for one year at 10% per annum reckoned half-yearly is:
Answer: Option
Explanation:
| S.I. = Rs |  |
1200 x 10 x 1 |  |
= Rs. 120. |
| 100 |
| C.I. = Rs. |  |
1200 x | |
1 + | 5 | |
2 | - 1200 |  |
= Rs. 123. |
| 100 |
Difference = Rs. (123 - 120) = Rs. 3.
Discussion:
53 comments Page 3 of 6.
Akanksha said:
1 decade ago
Time is half yearly. So why in SI = 1200*10*1/(100*2) half yearly is not done.
And in CI 1200 should not be subtracted but to make as SI is calculated yearly, the amount of CI which is calculated half yearly should be doubled to be annually.
And in CI 1200 should not be subtracted but to make as SI is calculated yearly, the amount of CI which is calculated half yearly should be doubled to be annually.
Naveen said:
10 years ago
To calculating S.I, considering 1 year while calculating C.I using half yearly basis. Why?
Sandy said:
9 years ago
They asked us to find the diff b/w SI and CI for one year only. But the case is, the interest is credited every 6 month once i.e) half yearly.
Since interest is credited half yearly for an annum,
Compound interest = p[1+(r/2)/100]^2n, where n = 1 year.
S.I calculation is same. Because interest is gonna be constant.
Hope you are clear now.
Since interest is credited half yearly for an annum,
Compound interest = p[1+(r/2)/100]^2n, where n = 1 year.
S.I calculation is same. Because interest is gonna be constant.
Hope you are clear now.
Santhiya said:
9 years ago
Yeah. I'm clear. Out off all the above solutions, I could say yours is the best.
S.I calculation will be same if we calculate interest for 1 year & 10% or with summation of two six months with 5% interest. Right?
S.I calculation will be same if we calculate interest for 1 year & 10% or with summation of two six months with 5% interest. Right?
Sandy said:
9 years ago
Yes @Santhiya you are upto the point. Anyhow SI gonna be the fixed interest for the months.
Haritha said:
9 years ago
Do we have any other method to solve this problem? If yes means, please tell me.
K.BHARGAVI said:
9 years ago
for one year S.I is ptr/100,
S.I = 120.
C.I : FOR HALF YEAR.
a = p(1 + (R/2)/100)^2 = 1200.
We know that,
A = P + C.I.
C.I = A - P,
= 1323 - 1200,
= 123.
Difference = C.I - S.I
= 123 - 120.
Difference = 3.
S.I = 120.
C.I : FOR HALF YEAR.
a = p(1 + (R/2)/100)^2 = 1200.
We know that,
A = P + C.I.
C.I = A - P,
= 1323 - 1200,
= 123.
Difference = C.I - S.I
= 123 - 120.
Difference = 3.
Himesh said:
9 years ago
Why do we need to calculate amount?
According to the question they only asked for difference between CI and SI.
According to the question they only asked for difference between CI and SI.
Praveen chauhan said:
9 years ago
Just used this formula:
Diffrence = (P * R * R/100 * 100).
Given P = 1200, half yearly compounded so rate becomes half and time becomes double.
Earlier - T = 1, R = 10%.
Now T = 2, R = 5%.
(1200 * 5 * 5/100 * 100) = Rs 3.00.
I hope you will understand better!
Thanks.
Diffrence = (P * R * R/100 * 100).
Given P = 1200, half yearly compounded so rate becomes half and time becomes double.
Earlier - T = 1, R = 10%.
Now T = 2, R = 5%.
(1200 * 5 * 5/100 * 100) = Rs 3.00.
I hope you will understand better!
Thanks.
Dhairya said:
9 years ago
Just use this formula:
si - ci = (r * r/10000) * p.
Where r = 5 as it is compounded half yearly.
I hope you will understand better!
si - ci = (r * r/10000) * p.
Where r = 5 as it is compounded half yearly.
I hope you will understand better!
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