Aptitude - Compound Interest - Discussion
Discussion Forum : Compound Interest - General Questions (Q.No. 13)
13.
The difference between simple interest and compound on Rs. 1200 for one year at 10% per annum reckoned half-yearly is:
Answer: Option
Explanation:
| S.I. = Rs |  |
1200 x 10 x 1 |  |
= Rs. 120. |
| 100 |
| C.I. = Rs. |  |
1200 x | |
1 + | 5 | |
2 | - 1200 |  |
= Rs. 123. |
| 100 |
Difference = Rs. (123 - 120) = Rs. 3.
Discussion:
53 comments Page 6 of 6.
Yogeshwar said:
4 years ago
Difference between S.I & C.I.
D=P[r/100]^2.
In question given is "reckoned " means "calculating" for half year so take half value in1200 is 600.
Now, 600[10/100]^2=60.
Let, C. I for halfyearly is p[1+(r/200)]^2n.
n=1/2 then 2 * n = 1,
600[1+(10/200)].
600*21/20]=63.
Now, 60-63=60.
D=P[r/100]^2.
In question given is "reckoned " means "calculating" for half year so take half value in1200 is 600.
Now, 600[10/100]^2=60.
Let, C. I for halfyearly is p[1+(r/200)]^2n.
n=1/2 then 2 * n = 1,
600[1+(10/200)].
600*21/20]=63.
Now, 60-63=60.
(4)
Chaitra Dhote said:
12 months ago
Very Easy SI and CI both will be calcuated Half Yearly,
New Rate = 10% (divided by) 2 = 5 %.
New Time= 1 year( multiply by)2= 2 Years.
Now SI = (PRT)/100 = (1200 x 5 x 2)/100 =120
Now CI For 1st Year 1200 x 5% = [60].
CI For 2nd Year 1200 x 5%= [60] + 1st Year's 60 x 5% =[3].
Total CI [60 + 60 + 3]= 123.
Total SI =120.
Ans= 123-120 =3.
New Rate = 10% (divided by) 2 = 5 %.
New Time= 1 year( multiply by)2= 2 Years.
Now SI = (PRT)/100 = (1200 x 5 x 2)/100 =120
Now CI For 1st Year 1200 x 5% = [60].
CI For 2nd Year 1200 x 5%= [60] + 1st Year's 60 x 5% =[3].
Total CI [60 + 60 + 3]= 123.
Total SI =120.
Ans= 123-120 =3.
(2)
Skywalker said:
1 month ago
S.I = 2 (PRT)/100 ,
T = 0.5,
= 120.
A = P(1+ R/2/100)^2
= 1323.
Then C.I = 1323 - 1200,
= 123
And we get, S.I - C.I = 3.
T = 0.5,
= 120.
A = P(1+ R/2/100)^2
= 1323.
Then C.I = 1323 - 1200,
= 123
And we get, S.I - C.I = 3.
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