Aptitude - Compound Interest - Discussion
Discussion Forum : Compound Interest - General Questions (Q.No. 13)
13.
The difference between simple interest and compound on Rs. 1200 for one year at 10% per annum reckoned half-yearly is:
Answer: Option
Explanation:
S.I. = Rs | ![]() |
1200 x 10 x 1 | ![]() |
= Rs. 120. |
100 |
C.I. = Rs. | ![]() |
1200 x | ![]() |
1 + | 5 | ![]() |
2 | - 1200 | ![]() |
= Rs. 123. |
100 |
Difference = Rs. (123 - 120) = Rs. 3.
Discussion:
53 comments Page 1 of 6.
Skywalker said:
1 month ago
S.I = 2 (PRT)/100 ,
T = 0.5,
= 120.
A = P(1+ R/2/100)^2
= 1323.
Then C.I = 1323 - 1200,
= 123
And we get, S.I - C.I = 3.
T = 0.5,
= 120.
A = P(1+ R/2/100)^2
= 1323.
Then C.I = 1323 - 1200,
= 123
And we get, S.I - C.I = 3.
Chaitra Dhote said:
12 months ago
Very Easy SI and CI both will be calcuated Half Yearly,
New Rate = 10% (divided by) 2 = 5 %.
New Time= 1 year( multiply by)2= 2 Years.
Now SI = (PRT)/100 = (1200 x 5 x 2)/100 =120
Now CI For 1st Year 1200 x 5% = [60].
CI For 2nd Year 1200 x 5%= [60] + 1st Year's 60 x 5% =[3].
Total CI [60 + 60 + 3]= 123.
Total SI =120.
Ans= 123-120 =3.
New Rate = 10% (divided by) 2 = 5 %.
New Time= 1 year( multiply by)2= 2 Years.
Now SI = (PRT)/100 = (1200 x 5 x 2)/100 =120
Now CI For 1st Year 1200 x 5% = [60].
CI For 2nd Year 1200 x 5%= [60] + 1st Year's 60 x 5% =[3].
Total CI [60 + 60 + 3]= 123.
Total SI =120.
Ans= 123-120 =3.
(2)
Yogeshwar said:
4 years ago
Difference between S.I & C.I.
D=P[r/100]^2.
In question given is "reckoned " means "calculating" for half year so take half value in1200 is 600.
Now, 600[10/100]^2=60.
Let, C. I for halfyearly is p[1+(r/200)]^2n.
n=1/2 then 2 * n = 1,
600[1+(10/200)].
600*21/20]=63.
Now, 60-63=60.
D=P[r/100]^2.
In question given is "reckoned " means "calculating" for half year so take half value in1200 is 600.
Now, 600[10/100]^2=60.
Let, C. I for halfyearly is p[1+(r/200)]^2n.
n=1/2 then 2 * n = 1,
600[1+(10/200)].
600*21/20]=63.
Now, 60-63=60.
(4)
Dibyajyoti Giri said:
4 years ago
I thought the simple interest was also calculated half-yearly. In that case, SI is 122 and CI is 123.
(3)
ARCHISA DAS said:
5 years ago
5/100 is given in the formula. In the formula, there is p*(1+r/100)^n.
Here the rate is given 5% so it has come 5/100.
Hope this helps.
Here the rate is given 5% so it has come 5/100.
Hope this helps.
(1)
Aneesha said:
5 years ago
If we calculate the simple interest considering 6 months duration one by one, rate won't be split, P, are remains constant whereas time splits to 1/2. While calculating CI, rate is split whereas time is increased.
(3)
Tamalika Roy said:
5 years ago
There's a shortcut formula.
Diff = sum(r/100)^n.
Here,
D = 1200(5/100)^2 (as half-yearly)
= Rs 3.
Diff = sum(r/100)^n.
Here,
D = 1200(5/100)^2 (as half-yearly)
= Rs 3.
(10)
Sovan said:
6 years ago
In the question it is given to compute the difference between CI and SI for 1 year.
Hence : SI= (P*R*T)/100 => (1200*10*1) /100 = 120
Now compute CI for the 1st half year, as it is computed half yearly:
A=P(1+(r/2)/100)^2n , here our n=1/2
=> A=1200(1+(10/2)/100)^2*1/2 => 1200(1+1/20) on computing we get A=1260
So our CI for the first half year is 1260-1200= 60.
Now as we are calculating the CI for 1 year, hence the amount (1260) which we got by calculating the Amount for the first half year becomes our Principal for the second half year.
So again using the formula: P(1+r/100)^n => 1260(1+(10/2)/100)^2*1/2
On computing we get A= 1323, So CI= 1323-1200= 123=> CI at the end of one year.
So as the difference between CI and SI is asked for 1 year.
Hence : CI-SI= 123-120 = 3 Ans.
Hence : SI= (P*R*T)/100 => (1200*10*1) /100 = 120
Now compute CI for the 1st half year, as it is computed half yearly:
A=P(1+(r/2)/100)^2n , here our n=1/2
=> A=1200(1+(10/2)/100)^2*1/2 => 1200(1+1/20) on computing we get A=1260
So our CI for the first half year is 1260-1200= 60.
Now as we are calculating the CI for 1 year, hence the amount (1260) which we got by calculating the Amount for the first half year becomes our Principal for the second half year.
So again using the formula: P(1+r/100)^n => 1260(1+(10/2)/100)^2*1/2
On computing we get A= 1323, So CI= 1323-1200= 123=> CI at the end of one year.
So as the difference between CI and SI is asked for 1 year.
Hence : CI-SI= 123-120 = 3 Ans.
(2)
BHARAT said:
6 years ago
Why didn't we take SI to be half-yearly. It should be 60 right?
(3)
Arjun said:
6 years ago
SI = 120
Given P = 1200, half-yearly compounded so rate becomes half and time becomes double.
1200 * 10.25/100 = 123,
CI-SI= 123-120 = 3.
Given P = 1200, half-yearly compounded so rate becomes half and time becomes double.
1200 * 10.25/100 = 123,
CI-SI= 123-120 = 3.
(2)
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