Aptitude - Clock - Discussion

Discussion Forum : Clock - General Questions (Q.No. 9)
9.
At what angle the hands of a clock are inclined at 15 minutes past 5?
58 1 °
2
64°
67 1 °
2
72 1 °
2
Answer: Option
Explanation:

Angle traced by hour hand in 21 hrs = 360 x 21 ° = 157 1 °
4 12 4 2

Angle traced by min. hand in 15 min. = 360 x 15 ° = 90°.
60

Required angle = 157 1 ° - 90° = 67 1 °
2 2

Discussion:
41 comments Page 3 of 5.

Udai said:   1 year ago
It is 5:15.
we can assume 15 as "3".
So 5-3 = 2*30+15/2= 60+7.5.
Answer= 67.5.
(1)

Vamshik said:   1 decade ago
I think (30*Hrs)-(11/2)*Mins is the correct formula for getting this answer.

Aarif said:   7 years ago
Use the formula.

=(11/2*min-30*hour),
11/2*15-30*5,
165/2-150,
135/2=67.5.

Srikanth said:   2 years ago
11/2 *m -30*h.
= 11/2*15 -30 * 5.
= 165/2 -150,
= 82.5-150,
= 67.5.
(5)

Mithilesh Naphade said:   9 years ago
Best way to find the angle between hr and min hand is 30H - 5.5M.

Ganesh said:   1 decade ago
21/4 = 5 hr 15 min = 5(15/60) = 5(1/4) = ((5*4)+1)/4 = 21/4.

Siyaram said:   1 decade ago
Angle between them 1 hour is 30 degree so 30+30+30/4=67.5.

Vasuroshan said:   1 decade ago
@ rekha

5 hrs and 15 min so

5+15/60=5+1/4

20+1/4=21/4

Guhan said:   1 decade ago
We can use the formula

Theta= (11(Minutes)/2)-30(Hour)

Nikhil said:   1 decade ago
21/4=5.25
0.25 is 1/4 part of 60min. i.e. 15min


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