Aptitude - Chain Rule - Discussion

Discussion Forum : Chain Rule - General Questions (Q.No. 6)
6.
A man completes of a job in 10 days. At this rate, how many more days will it takes him to finish the job?
5
6
7
7 1
2
Answer: Option
Explanation:

Work done = 5
8

Balance work = 1 - 5 = 3
8 8

Let the required number of days be x.

Then, 5 : 3 = :: 10 : x     5 x x = 3 x 10
8 8 8 8

x = 3 x 10 x 8
8 5

x = 6.

Discussion:
36 comments Page 3 of 4.

Gaurav Pant said:   1 decade ago
5/8 work completed in 10 days.

Total work will complete = 10*(8/5) = 80/5 = 16.

Therefore remaining work (1-5/8) done on = 16-10 days = 6 days.

Shaunak said:   1 decade ago
Take the problem in the following way:.

A man can complete 5/8 of a work in 10 days. How long does it take to complete 3/8 of the same work?

Priyanka said:   1 decade ago
@Chandrasekar

Its too simple logic..

Consider the work done be 1.

They have completed 5/8 of work.

So remaining is 1-(5/8)=(8-5)/8=3/8

Mithilesh kumar said:   1 decade ago
In 1 day (5/8)/10 = 0.0625 part work is done.

Hence,

No.of days taken to complete this = 1/0.0625 = 16.

Remaining days = 16-10 = 6.

GAGAn said:   5 years ago
5/8 of the work could be completed in 10 days.
So, full work could be completed in 10*8/5 = 16 days.
Extra days = 16 -10 = 6 days.
(1)

Bindu brisk said:   9 years ago
It's so simple:

Total of 8 parts 5 parts done in 10 days:

Remaining 3 parts in 6 days:

1 part = 2 days.

Sonu said:   1 decade ago
Job Day(s).
5/8 10
1/8 10/5=2
8/8
(i.e.=1) 2X8=16

Remaining Days = 16-10 = 6.

Ranjan said:   1 decade ago
Comapare these two No. 5 and 6 please clear me. I don't understand these two question.

Zareena said:   8 years ago
5/8 job = 10 days,
1 job = 10 * 8/5,
1 job = 16 days,
16 - 10 days = 6 days.

Revanth said:   3 years ago
5/8 in 10 days.

So remaining 3/8.
10*3/8 ÷ 5/8 = 10 * 3 * 8/8 * 5 = 6 days.
(1)


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