Aptitude - Chain Rule - Discussion
Discussion Forum : Chain Rule - General Questions (Q.No. 6)
6.
A man completes 
of a job in 10 days. At this rate, how many more days will it takes him to finish the job?
of a job in 10 days. At this rate, how many more days will it takes him to finish the job?
Answer: Option
Explanation:
| Work done = | 5 |
| 8 |
| Balance work = |  |
1 - | 5 |  |
= | 3 |
| 8 | 8 |
Let the required number of days be x.
| Then, | 5 | : | 3 | = :: 10 : x |  |
5 | x x = | 3 | x 10 |
| 8 | 8 | 8 | 8 |
 x = |
|
3 | x 10 x | 8 | |
| 8 | 5 |
x = 6.
Discussion:
36 comments Page 1 of 4.
Chophel said:
3 years ago
He completes 5/8 of the work in 10 days.
He can complete the work in
8/5 * 10 days,
= 80/5 days.
= 16 days.
He completed 10 days of work.
16-10= 6 days.
He can complete the work in
8/5 * 10 days,
= 80/5 days.
= 16 days.
He completed 10 days of work.
16-10= 6 days.
(6)
RAJAN said:
6 years ago
He completed 5 jobs out of 8, in 10 days so that means he completed 1 job in 2 days and to complete 3 more jobs (8-5=3) and he will take 6 days (3x2=6).
(2)
Revanth said:
3 years ago
5/8 in 10 days.
So remaining 3/8.
10*3/8 ÷ 5/8 = 10 * 3 * 8/8 * 5 = 6 days.
So remaining 3/8.
10*3/8 ÷ 5/8 = 10 * 3 * 8/8 * 5 = 6 days.
(1)
GAGAn said:
5 years ago
5/8 of the work could be completed in 10 days.
So, full work could be completed in 10*8/5 = 16 days.
Extra days = 16 -10 = 6 days.
So, full work could be completed in 10*8/5 = 16 days.
Extra days = 16 -10 = 6 days.
(1)
Venkat Ravi said:
7 years ago
Consider a job value is 100(not given).
8/3 of work is done in 10 days then,
(8/3)*100 = 62.5(ie.,62.5% of work is completed in 10 days then the remaining work will be 37.5).
For 10 days 67.5.
For single day=(67.5/10)=6.75(ie.,per day work).
Remaining days=(remaining work/per day work) = (37.5/6.75) = 6 days.
8/3 of work is done in 10 days then,
(8/3)*100 = 62.5(ie.,62.5% of work is completed in 10 days then the remaining work will be 37.5).
For 10 days 67.5.
For single day=(67.5/10)=6.75(ie.,per day work).
Remaining days=(remaining work/per day work) = (37.5/6.75) = 6 days.
Bindu brisk said:
9 years ago
It's so simple:
Total of 8 parts 5 parts done in 10 days:
Remaining 3 parts in 6 days:
1 part = 2 days.
Total of 8 parts 5 parts done in 10 days:
Remaining 3 parts in 6 days:
1 part = 2 days.
Gokul raj said:
9 years ago
The work of 5 parts done in 10 days.
So, 10/5 = 2 days of time taken to complete one part.
Then, 5/8 has 3 remain parts 3 * 2(days) = 6 days.
Thank you.
So, 10/5 = 2 days of time taken to complete one part.
Then, 5/8 has 3 remain parts 3 * 2(days) = 6 days.
Thank you.
Ram said:
9 years ago
Total work of job = 8,
Out of 8 he does 5 in 10 days (given in the question).
So, 5 work of a job = 10 days,
Therefore, 1 work of a job = 10/5 = 2 days,
Now remaining work are (8-5) = 3,
1 work = 2 days,
So, 3 work of a job = 3*2 = 6 days. (2+2+2).
Out of 8 he does 5 in 10 days (given in the question).
So, 5 work of a job = 10 days,
Therefore, 1 work of a job = 10/5 = 2 days,
Now remaining work are (8-5) = 3,
1 work = 2 days,
So, 3 work of a job = 3*2 = 6 days. (2+2+2).
Pavan Power star PK fan said:
9 years ago
He takes 10 days to complete 5/8 of the job.
In 1 day he does 5/80 of job.
If the job is complete then fraction will become 1.So (work done in 1 day) * (no. of days ) = 1.
Then, the number of days = 16.
But he did 10 days work already so the remaining days needed to complete the job is 6 days.
In 1 day he does 5/80 of job.
If the job is complete then fraction will become 1.So (work done in 1 day) * (no. of days ) = 1.
Then, the number of days = 16.
But he did 10 days work already so the remaining days needed to complete the job is 6 days.
Zareena said:
8 years ago
5/8 job = 10 days,
1 job = 10 * 8/5,
1 job = 16 days,
16 - 10 days = 6 days.
1 job = 10 * 8/5,
1 job = 16 days,
16 - 10 days = 6 days.
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