Aptitude - Chain Rule - Discussion
Discussion Forum : Chain Rule - General Questions (Q.No. 6)
6.
A man completes 
of a job in 10 days. At this rate, how many more days will it takes him to finish the job?
of a job in 10 days. At this rate, how many more days will it takes him to finish the job?
Answer: Option
Explanation:
| Work done = | 5 |
| 8 |
| Balance work = |  |
1 - | 5 |  |
= | 3 |
| 8 | 8 |
Let the required number of days be x.
| Then, | 5 | : | 3 | = :: 10 : x |  |
5 | x x = | 3 | x 10 |
| 8 | 8 | 8 | 8 |
 x = |
|
3 | x 10 x | 8 | |
| 8 | 5 |
x = 6.
Discussion:
36 comments Page 1 of 4.
Chandan said:
2 months ago
He completes 5/8 of the work in 10 days.
He can complete the work in,
8/5 * 10 days,
= 80/5 days.
= 16 days.
He completed 10 days of work.
16 - 10 = 6 days.
He can complete the work in,
8/5 * 10 days,
= 80/5 days.
= 16 days.
He completed 10 days of work.
16 - 10 = 6 days.
Chophel said:
3 years ago
He completes 5/8 of the work in 10 days.
He can complete the work in
8/5 * 10 days,
= 80/5 days.
= 16 days.
He completed 10 days of work.
16-10= 6 days.
He can complete the work in
8/5 * 10 days,
= 80/5 days.
= 16 days.
He completed 10 days of work.
16-10= 6 days.
(6)
Revanth said:
3 years ago
5/8 in 10 days.
So remaining 3/8.
10*3/8 ÷ 5/8 = 10 * 3 * 8/8 * 5 = 6 days.
So remaining 3/8.
10*3/8 ÷ 5/8 = 10 * 3 * 8/8 * 5 = 6 days.
(1)
Anushree said:
3 years ago
@All.
Simply;
First of all, we need to divide 5 by 10, the answer will be 0.5/half so we need to draw two lines for each day, for ex ll-1,ll-2 etc.
And after it comes to 5 just continue drawing two lines for a day (so we will do like this- ll-6, ll-7 and ll-8 )
Now we need to see the number of lines we have drawn, that is 6, then the answer will be 6.
Thank you.
Simply;
First of all, we need to divide 5 by 10, the answer will be 0.5/half so we need to draw two lines for each day, for ex ll-1,ll-2 etc.
And after it comes to 5 just continue drawing two lines for a day (so we will do like this- ll-6, ll-7 and ll-8 )
Now we need to see the number of lines we have drawn, that is 6, then the answer will be 6.
Thank you.
GAGAn said:
5 years ago
5/8 of the work could be completed in 10 days.
So, full work could be completed in 10*8/5 = 16 days.
Extra days = 16 -10 = 6 days.
So, full work could be completed in 10*8/5 = 16 days.
Extra days = 16 -10 = 6 days.
(1)
Jefferson said:
6 years ago
5/8 of the work is completed in 10 days.
So we get the remaining work = (1-5/8).
= 3/8.
Completing work is directly proportional to days.
Hence direct proportion where x/y = constant.
Let we take the time taken to complete 3/8 be x.
And therefore = 10/(5/8) = 16,
for 3/8=8x/3,
thus 8x/3=16,
8x = 48,
and x = 6days.
So we get the remaining work = (1-5/8).
= 3/8.
Completing work is directly proportional to days.
Hence direct proportion where x/y = constant.
Let we take the time taken to complete 3/8 be x.
And therefore = 10/(5/8) = 16,
for 3/8=8x/3,
thus 8x/3=16,
8x = 48,
and x = 6days.
Pujan Das said:
6 years ago
5/8 is completed in 10 days.
Hence, 1 (100%) will be completed in (10*8)/5 = 16 days.
The rate of work remains constant. (important point).
Thus, Remaining days = total days - elapsed = 16 - 10 = 6 days.
Hence, 1 (100%) will be completed in (10*8)/5 = 16 days.
The rate of work remains constant. (important point).
Thus, Remaining days = total days - elapsed = 16 - 10 = 6 days.
RAJAN said:
6 years ago
He completed 5 jobs out of 8, in 10 days so that means he completed 1 job in 2 days and to complete 3 more jobs (8-5=3) and he will take 6 days (3x2=6).
(2)
Venkat Ravi said:
7 years ago
Consider a job value is 100(not given).
8/3 of work is done in 10 days then,
(8/3)*100 = 62.5(ie.,62.5% of work is completed in 10 days then the remaining work will be 37.5).
For 10 days 67.5.
For single day=(67.5/10)=6.75(ie.,per day work).
Remaining days=(remaining work/per day work) = (37.5/6.75) = 6 days.
8/3 of work is done in 10 days then,
(8/3)*100 = 62.5(ie.,62.5% of work is completed in 10 days then the remaining work will be 37.5).
For 10 days 67.5.
For single day=(67.5/10)=6.75(ie.,per day work).
Remaining days=(remaining work/per day work) = (37.5/6.75) = 6 days.
Shubham said:
7 years ago
A garrison of 750 men has provision for 20 weeks if, at the end of 4 weeks, they are reinforced by 450 men, how long the provision will last?
How to solve this by using the chain rule? Please help me.
How to solve this by using the chain rule? Please help me.
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