Aptitude - Chain Rule - Discussion
Discussion Forum : Chain Rule - General Questions (Q.No. 6)
6.
A man completes 
of a job in 10 days. At this rate, how many more days will it takes him to finish the job?
of a job in 10 days. At this rate, how many more days will it takes him to finish the job?
Answer: Option
Explanation:
| Work done = | 5 |
| 8 |
| Balance work = |  |
1 - | 5 |  |
= | 3 |
| 8 | 8 |
Let the required number of days be x.
| Then, | 5 | : | 3 | = :: 10 : x |  |
5 | x x = | 3 | x 10 |
| 8 | 8 | 8 | 8 |
 x = |
|
3 | x 10 x | 8 | |
| 8 | 5 |
x = 6.
Discussion:
36 comments Page 2 of 4.
Sowmiya said:
8 years ago
Very nice explanation @Bhadra.
Ram said:
8 years ago
Look another eg;
1/2 work = 5 day
Then,
Getting completed ie,
LHS should be 1.
cross multiply.
ie
1=2*5.
=10days.
Similarly,
5/8=10.
1= 8/5*10.
= 16.
1/2 work = 5 day
Then,
Getting completed ie,
LHS should be 1.
cross multiply.
ie
1=2*5.
=10days.
Similarly,
5/8=10.
1= 8/5*10.
= 16.
Zareena said:
8 years ago
5/8 job = 10 days,
1 job = 10 * 8/5,
1 job = 16 days,
16 - 10 days = 6 days.
1 job = 10 * 8/5,
1 job = 16 days,
16 - 10 days = 6 days.
Pavan Power star PK fan said:
9 years ago
He takes 10 days to complete 5/8 of the job.
In 1 day he does 5/80 of job.
If the job is complete then fraction will become 1.So (work done in 1 day) * (no. of days ) = 1.
Then, the number of days = 16.
But he did 10 days work already so the remaining days needed to complete the job is 6 days.
In 1 day he does 5/80 of job.
If the job is complete then fraction will become 1.So (work done in 1 day) * (no. of days ) = 1.
Then, the number of days = 16.
But he did 10 days work already so the remaining days needed to complete the job is 6 days.
Ram said:
9 years ago
Total work of job = 8,
Out of 8 he does 5 in 10 days (given in the question).
So, 5 work of a job = 10 days,
Therefore, 1 work of a job = 10/5 = 2 days,
Now remaining work are (8-5) = 3,
1 work = 2 days,
So, 3 work of a job = 3*2 = 6 days. (2+2+2).
Out of 8 he does 5 in 10 days (given in the question).
So, 5 work of a job = 10 days,
Therefore, 1 work of a job = 10/5 = 2 days,
Now remaining work are (8-5) = 3,
1 work = 2 days,
So, 3 work of a job = 3*2 = 6 days. (2+2+2).
Gokul raj said:
9 years ago
The work of 5 parts done in 10 days.
So, 10/5 = 2 days of time taken to complete one part.
Then, 5/8 has 3 remain parts 3 * 2(days) = 6 days.
Thank you.
So, 10/5 = 2 days of time taken to complete one part.
Then, 5/8 has 3 remain parts 3 * 2(days) = 6 days.
Thank you.
Bindu brisk said:
9 years ago
It's so simple:
Total of 8 parts 5 parts done in 10 days:
Remaining 3 parts in 6 days:
1 part = 2 days.
Total of 8 parts 5 parts done in 10 days:
Remaining 3 parts in 6 days:
1 part = 2 days.
Kathik said:
10 years ago
Given that 5/8 (job) = 10 days.
Then for full job completion take:
1(job) = 10(8/5).
= 16 days.
So in question asked how many remaining days to finish the job.
So Total days - Given days.
= 16 - 10 = 6 days.
Then for full job completion take:
1(job) = 10(8/5).
= 16 days.
So in question asked how many remaining days to finish the job.
So Total days - Given days.
= 16 - 10 = 6 days.
Gaurav Pant said:
1 decade ago
5/8 work completed in 10 days.
Total work will complete = 10*(8/5) = 80/5 = 16.
Therefore remaining work (1-5/8) done on = 16-10 days = 6 days.
Total work will complete = 10*(8/5) = 80/5 = 16.
Therefore remaining work (1-5/8) done on = 16-10 days = 6 days.
Sankar said:
1 decade ago
A's 10 days work 5/8.
Then A's one day 5/10 = 0.50.
Remaining work 3/8. So 2 days 1 work over.
Therefore remaining work is 3*2 = 6 days remaining over.
Then A's one day 5/10 = 0.50.
Remaining work 3/8. So 2 days 1 work over.
Therefore remaining work is 3*2 = 6 days remaining over.
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