Aptitude - Chain Rule - Discussion
Discussion Forum : Chain Rule - General Questions (Q.No. 6)
6.
A man completes 
of a job in 10 days. At this rate, how many more days will it takes him to finish the job?
of a job in 10 days. At this rate, how many more days will it takes him to finish the job?
Answer: Option
Explanation:
| Work done = | 5 |
| 8 |
| Balance work = |  |
1 - | 5 |  |
= | 3 |
| 8 | 8 |
Let the required number of days be x.
| Then, | 5 | : | 3 | = :: 10 : x |  |
5 | x x = | 3 | x 10 |
| 8 | 8 | 8 | 8 |
 x = |
|
3 | x 10 x | 8 | |
| 8 | 5 |
x = 6.
Discussion:
37 comments Page 2 of 4.
Shubham said:
8 years ago
A garrison of 750 men has provision for 20 weeks if, at the end of 4 weeks, they are reinforced by 450 men, how long the provision will last?
How to solve this by using the chain rule? Please help me.
How to solve this by using the chain rule? Please help me.
Sowmiya said:
9 years ago
Very nice explanation @Bhadra.
Ram said:
9 years ago
Look another eg;
1/2 work = 5 day
Then,
Getting completed ie,
LHS should be 1.
cross multiply.
ie
1=2*5.
=10days.
Similarly,
5/8=10.
1= 8/5*10.
= 16.
1/2 work = 5 day
Then,
Getting completed ie,
LHS should be 1.
cross multiply.
ie
1=2*5.
=10days.
Similarly,
5/8=10.
1= 8/5*10.
= 16.
Zareena said:
9 years ago
5/8 job = 10 days,
1 job = 10 * 8/5,
1 job = 16 days,
16 - 10 days = 6 days.
1 job = 10 * 8/5,
1 job = 16 days,
16 - 10 days = 6 days.
Pavan Power star PK fan said:
10 years ago
He takes 10 days to complete 5/8 of the job.
In 1 day he does 5/80 of job.
If the job is complete then fraction will become 1.So (work done in 1 day) * (no. of days ) = 1.
Then, the number of days = 16.
But he did 10 days work already so the remaining days needed to complete the job is 6 days.
In 1 day he does 5/80 of job.
If the job is complete then fraction will become 1.So (work done in 1 day) * (no. of days ) = 1.
Then, the number of days = 16.
But he did 10 days work already so the remaining days needed to complete the job is 6 days.
Ram said:
10 years ago
Total work of job = 8,
Out of 8 he does 5 in 10 days (given in the question).
So, 5 work of a job = 10 days,
Therefore, 1 work of a job = 10/5 = 2 days,
Now remaining work are (8-5) = 3,
1 work = 2 days,
So, 3 work of a job = 3*2 = 6 days. (2+2+2).
Out of 8 he does 5 in 10 days (given in the question).
So, 5 work of a job = 10 days,
Therefore, 1 work of a job = 10/5 = 2 days,
Now remaining work are (8-5) = 3,
1 work = 2 days,
So, 3 work of a job = 3*2 = 6 days. (2+2+2).
Gokul raj said:
10 years ago
The work of 5 parts done in 10 days.
So, 10/5 = 2 days of time taken to complete one part.
Then, 5/8 has 3 remain parts 3 * 2(days) = 6 days.
Thank you.
So, 10/5 = 2 days of time taken to complete one part.
Then, 5/8 has 3 remain parts 3 * 2(days) = 6 days.
Thank you.
Bindu brisk said:
1 decade ago
It's so simple:
Total of 8 parts 5 parts done in 10 days:
Remaining 3 parts in 6 days:
1 part = 2 days.
Total of 8 parts 5 parts done in 10 days:
Remaining 3 parts in 6 days:
1 part = 2 days.
Kathik said:
1 decade ago
Given that 5/8 (job) = 10 days.
Then for full job completion take:
1(job) = 10(8/5).
= 16 days.
So in question asked how many remaining days to finish the job.
So Total days - Given days.
= 16 - 10 = 6 days.
Then for full job completion take:
1(job) = 10(8/5).
= 16 days.
So in question asked how many remaining days to finish the job.
So Total days - Given days.
= 16 - 10 = 6 days.
Gaurav Pant said:
1 decade ago
5/8 work completed in 10 days.
Total work will complete = 10*(8/5) = 80/5 = 16.
Therefore remaining work (1-5/8) done on = 16-10 days = 6 days.
Total work will complete = 10*(8/5) = 80/5 = 16.
Therefore remaining work (1-5/8) done on = 16-10 days = 6 days.
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