Aptitude - Chain Rule - Discussion

Discussion Forum : Chain Rule - General Questions (Q.No. 6)
6.
A man completes of a job in 10 days. At this rate, how many more days will it takes him to finish the job?
5
6
7
7 1
2
Answer: Option
Explanation:

Work done = 5
8

Balance work = 1 - 5 = 3
8 8

Let the required number of days be x.

Then, 5 : 3 = :: 10 : x     5 x x = 3 x 10
8 8 8 8

x = 3 x 10 x 8
8 5

x = 6.

Discussion:
36 comments Page 3 of 4.

Ruk said:   1 decade ago
From 8/8 of total work, 5/8 part done in 10 days.

For one part he took 2 days.
10/5 = 2.

Then balance 3/8 part he will take.
3x2 days = 6 days.

Sonu said:   1 decade ago
Job Day(s).
5/8 10
1/8 10/5=2
8/8
(i.e.=1) 2X8=16

Remaining Days = 16-10 = 6.

Satish said:   1 decade ago
5/8 job = 10 days.

1 job = 10*8/5 = 16.

Remaining days = 16-10 = 6.

Mithilesh kumar said:   1 decade ago
In 1 day (5/8)/10 = 0.0625 part work is done.

Hence,

No.of days taken to complete this = 1/0.0625 = 16.

Remaining days = 16-10 = 6.

Sourabh said:   1 decade ago
@bhadra
hey nice explaination, thanks it helped me alot

Shahid said:   1 decade ago
It can be solved this way also
To complete 5/8 part --- 10 days
To complete 8/8 parts ---- ? days

Solving, {(8/8) x 10}/{5/8} = 16 days

Therefore remaining days = 160- 10 = 6 days

Chalam said:   1 decade ago
Bhadra & Avijeet,

Nice explanations.

Thanks

Avijeet said:   1 decade ago
Hey guys its very easy...

5/8 work can be done in 10 days

So 1 work can be done in 10/(5/8) days=10*8/5=16 days

Hence remaining(1-5/8=3/8)work can be done in 16*3/8
=6 days

Bhadra said:   1 decade ago
Very easy
For 5 parts work he takes 10days
for 3 parts ?

3*10/5=6days

Priyanka said:   1 decade ago
@Chandrasekar

Its too simple logic..

Consider the work done be 1.

They have completed 5/8 of work.

So remaining is 1-(5/8)=(8-5)/8=3/8


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