Aptitude - Chain Rule - Discussion
Discussion Forum : Chain Rule - General Questions (Q.No. 6)
6.
A man completes 
of a job in 10 days. At this rate, how many more days will it takes him to finish the job?
of a job in 10 days. At this rate, how many more days will it takes him to finish the job?
Answer: Option
Explanation:
| Work done = | 5 |
| 8 |
| Balance work = |  |
1 - | 5 |  |
= | 3 |
| 8 | 8 |
Let the required number of days be x.
| Then, | 5 | : | 3 | = :: 10 : x |  |
5 | x x = | 3 | x 10 |
| 8 | 8 | 8 | 8 |
 x = |
|
3 | x 10 x | 8 | |
| 8 | 5 |
x = 6.
Discussion:
36 comments Page 2 of 4.
Shahid said:
1 decade ago
It can be solved this way also
To complete 5/8 part --- 10 days
To complete 8/8 parts ---- ? days
Solving, {(8/8) x 10}/{5/8} = 16 days
Therefore remaining days = 160- 10 = 6 days
To complete 5/8 part --- 10 days
To complete 8/8 parts ---- ? days
Solving, {(8/8) x 10}/{5/8} = 16 days
Therefore remaining days = 160- 10 = 6 days
Mr.Romana said:
1 decade ago
Its so simple...
work done in one day:5/8*10=1/16
remaining work is:1-5/8=3/8
3/8*8/3=1/6
1/6+1/6+1/6+1/6+1/6+1/6=1
it means the remaining work can be done in 6 days
work done in one day:5/8*10=1/16
remaining work is:1-5/8=3/8
3/8*8/3=1/6
1/6+1/6+1/6+1/6+1/6+1/6=1
it means the remaining work can be done in 6 days
Chandan said:
2 months ago
He completes 5/8 of the work in 10 days.
He can complete the work in,
8/5 * 10 days,
= 80/5 days.
= 16 days.
He completed 10 days of work.
16 - 10 = 6 days.
He can complete the work in,
8/5 * 10 days,
= 80/5 days.
= 16 days.
He completed 10 days of work.
16 - 10 = 6 days.
Chophel said:
3 years ago
He completes 5/8 of the work in 10 days.
He can complete the work in
8/5 * 10 days,
= 80/5 days.
= 16 days.
He completed 10 days of work.
16-10= 6 days.
He can complete the work in
8/5 * 10 days,
= 80/5 days.
= 16 days.
He completed 10 days of work.
16-10= 6 days.
(6)
Sankar said:
1 decade ago
A's 10 days work 5/8.
Then A's one day 5/10 = 0.50.
Remaining work 3/8. So 2 days 1 work over.
Therefore remaining work is 3*2 = 6 days remaining over.
Then A's one day 5/10 = 0.50.
Remaining work 3/8. So 2 days 1 work over.
Therefore remaining work is 3*2 = 6 days remaining over.
Gokul raj said:
9 years ago
The work of 5 parts done in 10 days.
So, 10/5 = 2 days of time taken to complete one part.
Then, 5/8 has 3 remain parts 3 * 2(days) = 6 days.
Thank you.
So, 10/5 = 2 days of time taken to complete one part.
Then, 5/8 has 3 remain parts 3 * 2(days) = 6 days.
Thank you.
Ram said:
8 years ago
Look another eg;
1/2 work = 5 day
Then,
Getting completed ie,
LHS should be 1.
cross multiply.
ie
1=2*5.
=10days.
Similarly,
5/8=10.
1= 8/5*10.
= 16.
1/2 work = 5 day
Then,
Getting completed ie,
LHS should be 1.
cross multiply.
ie
1=2*5.
=10days.
Similarly,
5/8=10.
1= 8/5*10.
= 16.
RAJAN said:
6 years ago
He completed 5 jobs out of 8, in 10 days so that means he completed 1 job in 2 days and to complete 3 more jobs (8-5=3) and he will take 6 days (3x2=6).
(2)
M.v.krishna said:
1 decade ago
work days
5/8 10
8/8 x
5x/8=10
x=16
total work 16 days
remaining to do = (16-10) days
= 6 days
5/8 10
8/8 x
5x/8=10
x=16
total work 16 days
remaining to do = (16-10) days
= 6 days
Ruk said:
1 decade ago
From 8/8 of total work, 5/8 part done in 10 days.
For one part he took 2 days.
10/5 = 2.
Then balance 3/8 part he will take.
3x2 days = 6 days.
For one part he took 2 days.
10/5 = 2.
Then balance 3/8 part he will take.
3x2 days = 6 days.
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