Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 10)
10.
On 8th Feb, 2005 it was Tuesday. What was the day of the week on 8th Feb, 2004?
Answer: Option
Explanation:
The year 2004 is a leap year. It has 2 odd days.
The day on 8th Feb, 2004 is 2 days before the day on 8th Feb, 2005.
Hence, this day is Sunday.
Discussion:
48 comments Page 3 of 5.
Nibedita Behera said:
6 years ago
Why the no of odd days of the month of January is not counted?
Revathi said:
7 years ago
@All.
Normal year if (2013)- 1 odd day.
For leap year - 2 odd days .
Normal year if (2013)- 1 odd day.
For leap year - 2 odd days .
Chhotu kumar said:
3 months ago
0 = SUNDAY.
1 = MONDAY.
2 = TUESDAY.
3 = WEDNESDAY.
4 = THURSDAY.
5 = FRIDAY.
6 = SATURDAY.
We need to split that year of 2004.
=> 1600 + 400 + 3 + (Jan+8).
=> 0 + 0 + 3(1) + (3+8).(Here January Have 3 odd day then also we put 3 in there).
Substitute all the values.
3 + 3 + 8 = 14(day).
=>14/7 =2(weeks)
=>2 weeks + 0 odd day.
So, the Answer is SUNDAY.
1 = MONDAY.
2 = TUESDAY.
3 = WEDNESDAY.
4 = THURSDAY.
5 = FRIDAY.
6 = SATURDAY.
We need to split that year of 2004.
=> 1600 + 400 + 3 + (Jan+8).
=> 0 + 0 + 3(1) + (3+8).(Here January Have 3 odd day then also we put 3 in there).
Substitute all the values.
3 + 3 + 8 = 14(day).
=>14/7 =2(weeks)
=>2 weeks + 0 odd day.
So, the Answer is SUNDAY.
Venu said:
8 years ago
Very nice answer @Bittu.
Bittu said:
8 years ago
We are supposed to know the weekday on 8th Feb. 2004.
To all those who have doubt.
2004 = 1600 + 400 + 2001, 2002, 2003, (31 + 8 days of feb. ).
So odd days for the 1600 year = 0 odd days.
Odd days for 400 year = 0 odd days.
2001, 2002, 2003 all three are an ordinary year so odd days will be =3*1= 3 odd days.
And in 2004 total time period will be of 39 days ----> means 39/7= 5 weeks + 4 odd days.
So total odd days will be = 3+4= 7 (means 0 odd days).
So we finally got 0 odd days which means Sunday.
Hope you got it.
To all those who have doubt.
2004 = 1600 + 400 + 2001, 2002, 2003, (31 + 8 days of feb. ).
So odd days for the 1600 year = 0 odd days.
Odd days for 400 year = 0 odd days.
2001, 2002, 2003 all three are an ordinary year so odd days will be =3*1= 3 odd days.
And in 2004 total time period will be of 39 days ----> means 39/7= 5 weeks + 4 odd days.
So total odd days will be = 3+4= 7 (means 0 odd days).
So we finally got 0 odd days which means Sunday.
Hope you got it.
Gipu said:
8 years ago
2000=0 odd day,
3 normal yr=3*1=3,
8 fabry= january 3 odd dys +8,
since day= 0+3+3+8=14/7=0.
The correct answer is Sunday.
3 normal yr=3*1=3,
8 fabry= january 3 odd dys +8,
since day= 0+3+3+8=14/7=0.
The correct answer is Sunday.
Amey said:
8 years ago
Leap year means extra day in year which is 366. Since 2004 is leap year it has already surpassed day which would have been Sunday if it wasn't leap year. Correct answer is Monday.
Amogh said:
9 years ago
Total days passed from 8th Feb 2005 - 9th Feb 2004 is 366 days.
Therefore, the number of odd days is 2.
Meaning 9th Feb is a Wednesday(1 = Same day, 2 = Next day and so on). So, 8th Feb 2004 has to be Tuesday.
Therefore, the number of odd days is 2.
Meaning 9th Feb is a Wednesday(1 = Same day, 2 = Next day and so on). So, 8th Feb 2004 has to be Tuesday.
Ghulam said:
1 decade ago
Can any body help for me. How to solve calendar problems?
Amit kumar said:
1 decade ago
It is simple date given 8th feb 2005, a 366 days before date is 8th feb 2004. Simple divide 366/7, we get 2 remainder. Then subtract 2 days from tuesday its sunday.
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