Aptitude - Calendar - Discussion

Discussion Forum : Calendar - General Questions (Q.No. 10)
10.
On 8th Feb, 2005 it was Tuesday. What was the day of the week on 8th Feb, 2004?
Tuesday
Monday
Sunday
Wednesday
Answer: Option
Explanation:

The year 2004 is a leap year. It has 2 odd days.

The day on 8th Feb, 2004 is 2 days before the day on 8th Feb, 2005.

Hence, this day is Sunday.

Discussion:
48 comments Page 5 of 5.

Sumanth geras said:   1 decade ago
Guys 8th Feb 2004 is Sunday.

But by using the formula.

Day = Date+Month code+(x-1990)+(x-1990) /4.

We are not getting it as Sunday.

Can anyone explain what is problem with our formula and what went wrong?

Kirankumar said:   1 decade ago
Can any say how to solve this problem?

On June 28th 1987 is Saturday the day of the June 20th 1985 is?

Basivi reddy said:   10 years ago
Day code: 20.

Last two digits: 85.

Month code: 5.

Century code: 0.

Leap years: 1.

Total: 20 + 85 + 5 + 0 + 1.

Answer is Tuesday.

Bharath said:   10 years ago
What was the day of the week on 6th march 2004?

How to solve this question?

Pintu said:   9 years ago
@Shekher Anand Mishra

You Need to remember this thing.
i.e
Year Code
1600-1699=6
1700-1799=4
1800-1899=2
1900-1999=0
2000-2099=6
2100-2199=4
2200-2299=2
2300-2399=0
.
.
.
.and so on...

Month Code
Jan-0
feb-3
Mar-3
Apr-6
May-1
June-4
July-6
Aug-2
Sep-5
Oct-0
Nov-3
Dec-5

Day Code
Sun-0
Mon 1
Tue 2
Wed 3
Thr 4
Fri 5
Sat 6

Kavya said:   1 decade ago
I didn't understand exactly. Any one can please explain this to me.

Shwetank verma said:   9 years ago
Answer will be MONDAY.

Chintu said:   9 years ago
In this question, we are assuming that 2005 is not a leap year and 2004 as a leap year; every non-year odd days gets incremented by 1 and leap year increments by 2 the same subtract the odd days if you calculate in reverse order.

Considering our case we are calculating from 2005 to 2004 and since 2004 is a leap year subtract 2 days (i.e) Tuesday - 2 = Sunday.


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