Aptitude - Calendar - Discussion

Discussion Forum : Calendar - General Questions (Q.No. 4)
4.
What will be the day of the week 15th August, 2010?
Sunday
Monday
Tuesday
Friday
Answer: Option
Explanation:

15th August, 2010 = (2009 years + Period 1.1.2010 to 15.8.2010)

Odd days in 1600 years = 0

Odd days in 400 years = 0

9 years = (2 leap years + 7 ordinary years) = (2 x 2 + 7 x 1) = 11 odd days 4 odd days.

Jan.  Feb.   March    April    May  June  July  Aug. 
(31 +  28  +  31   +   30   +  31  + 30  + 31  + 15) = 227 days

227 days = (32 weeks + 3 days) 3 odd days.

Total number of odd days = (0 + 0 + 4 + 3) = 7 0 odd days.

Given day is Sunday.

Discussion:
95 comments Page 9 of 10.

Gopakumar said:   1 decade ago
Is anyone have the simplest way to give answer to this question? How can we understand the year said is leap year?

Ayushi said:   1 decade ago
I can't understand please anyone understand me in easy language.

Naveen said:   1 decade ago
We have 365 days for normal year, 366 days for leap year. So how no of odd days in 400 years is '0'.

Smita Deshmukh said:   1 decade ago
Given that 15th august, 2010.

1) Add day and last two digits of the year 15+10 = 25.

2) Divide last two digit of the year by 4, so 10/4 = 2.

3) Add quotient value to step 1.

= 25+2+2(month code)+6(year code) = 35.

4) Divide 35/7 = 5 it means remainder is 0(day code) Sunday.

Sumit said:   1 decade ago
11 odd days= 4 odd days. Can't understand.

Harshad said:   1 decade ago
What if February of year 2010 has 29 days? We have considered it to be 28 every time?

Priyanka said:   1 decade ago
@Selva.

If the year is divisible by 4 that year is called as leap year.

Priyanka said:   1 decade ago
@Ayesha.

9 years should be multiply by 4.

9/4 = 2 i.e 2 leap years.
9-2 = 7 i.e 7 ordinary years.

Selvi said:   1 decade ago
How to find the leap years? Anyone guys explain me I Can't understand Please help ME.

Kiran said:   1 decade ago
Please explain how

Total no of odd days = (0+0+4+3) = 7?


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