Aptitude - Calendar - Discussion

How 1600 and 400 gets 0 odd days ?

Sumit,

11 days are left and in those 11 days,week days (7) are subtracted so the remaining are 11-7=4 odd days.

Please explain 24-2-2015; Above date is what day of the week;

1600 = 0 odd days.

400 years = 0 odd days.

15 years will be remained.

15 year will have (3 leap years + 12 ordinary years).

= (3*2+1*12) = (6+12) = 18 = 7+7+4 = 4 odd days.

8 = 1 week+1 day.

(0+0+4+1) = 5 days = Friday.

What is the day on 8th January 2015 please explain briefly?

How to find month code, day code and year code?

So each year has one odd day and leap year has 2 odd days for every 100 years 100+24 odd days but after every 7 days the same day repeats for example today is Saturday after 7 days will be Saturday basing on this we neglect multiples of 7 and by dividing 124 with 7 we get 5 odd days.

So 100 years have 5 odd days but for every 400 years one day is added based on earth's rotation don't ask me about that so 400 years have 20+1 odd days which means 3 weeks and can be neglected as same day appears after any number of complete weeks.

1 year means 365 days it has one odd day after divide with 7 so if this year starts with Sunday then next year starts with Monday but if this year is leap year that means a multiple of 4 then next year starts with Tuesday.

Let me make it clear 0 means Sunday 1 means Monday 2 means Tuesday 3 means Wednesday 4 means Thursday 5 means Friday 6 means Saturday 7 means 0 in terms of odd days.

How you take 1600 and 400? I can't understand please tell me.