Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 4)
4.
What will be the day of the week 15th August, 2010?
Answer: Option
Explanation:
15th August, 2010 = (2009 years + Period 1.1.2010 to 15.8.2010)
Odd days in 1600 years = 0
Odd days in 400 years = 0
9 years = (2 leap years + 7 ordinary years) = (2 x 2 + 7 x 1) = 11 odd days 
4 odd days.
Jan. Feb. March April May June July Aug. (31 + 28 + 31 + 30 + 31 + 30 + 31 + 15) = 227 days
227 days = (32 weeks + 3 days) 3 odd days.
Total number of odd days = (0 + 0 + 4 + 3) = 7 0 odd days.
Given day is Sunday.
Discussion:
95 comments Page 6 of 10.
Harshad said:
1 decade ago
What if February of year 2010 has 29 days? We have considered it to be 28 every time?
Muzige said:
6 years ago
@Vaibhav.
In the formula f = k + (13m-1)/5 +d + (d/4)+(c/4)-2c, how to determine m?
In the formula f = k + (13m-1)/5 +d + (d/4)+(c/4)-2c, how to determine m?
Bidhya said:
9 years ago
Please help me to understand. Why a total number of odd days = 0 + 0 + 4 + 3 = 7.
Saipreethi said:
7 years ago
How can I find, if they have given the years in 1500 and 1600? Please explain.
Anil Kumar said:
1 decade ago
My dear how take 1600 years and 400 years And how leap year multiply by 2X2?
Akhil said:
1 decade ago
@Gpvsai : 15+2+10+2+6 = 35.
So, dividing 35 by 7 we get 5 which is friday.
So, dividing 35 by 7 we get 5 which is friday.
Nithya said:
1 decade ago
How for march the value of month is 6? I don't understand the month value.
Salil chaudhary said:
9 years ago
@Bidhya. When 7 is divided by 7 it gives remainder as 0. So odd days = 0.
Gokila said:
9 years ago
7/7= 0 remaider.
So, 7 ,14, 21, 28, 35 = have been considered as Sunday.
So, 7 ,14, 21, 28, 35 = have been considered as Sunday.
Priyanka said:
1 decade ago
@Selva.
If the year is divisible by 4 that year is called as leap year.
If the year is divisible by 4 that year is called as leap year.
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