Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 4)
4.
What will be the day of the week 15th August, 2010?
Answer: Option
Explanation:
15th August, 2010 = (2009 years + Period 1.1.2010 to 15.8.2010)
Odd days in 1600 years = 0
Odd days in 400 years = 0
9 years = (2 leap years + 7 ordinary years) = (2 x 2 + 7 x 1) = 11 odd days 4 odd days.
Jan. Feb. March April May June July Aug. (31 + 28 + 31 + 30 + 31 + 30 + 31 + 15) = 227 days
227 days = (32 weeks + 3 days)
3 odd days.
Total number of odd days = (0 + 0 + 4 + 3) = 7 0 odd days.
Given day is Sunday.
Discussion:
95 comments Page 5 of 10.
Meghna said:
1 decade ago
How you take 1600 and 400? I can't understand please tell me.
Krishna chaitu said:
1 decade ago
Let me make it clear 0 means Sunday 1 means Monday 2 means Tuesday 3 means Wednesday 4 means Thursday 5 means Friday 6 means Saturday 7 means 0 in terms of odd days.
Krishnachaitu said:
1 decade ago
1 year means 365 days it has one odd day after divide with 7 so if this year starts with Sunday then next year starts with Monday but if this year is leap year that means a multiple of 4 then next year starts with Tuesday.
Krishnachaitu said:
1 decade ago
So each year has one odd day and leap year has 2 odd days for every 100 years 100+24 odd days but after every 7 days the same day repeats for example today is Saturday after 7 days will be Saturday basing on this we neglect multiples of 7 and by dividing 124 with 7 we get 5 odd days.
So 100 years have 5 odd days but for every 400 years one day is added based on earth's rotation don't ask me about that so 400 years have 20+1 odd days which means 3 weeks and can be neglected as same day appears after any number of complete weeks.
So 100 years have 5 odd days but for every 400 years one day is added based on earth's rotation don't ask me about that so 400 years have 20+1 odd days which means 3 weeks and can be neglected as same day appears after any number of complete weeks.
Maheshwaree said:
10 years ago
How to find month code, day code and year code?
Venkat said:
10 years ago
What is the day on 8th January 2015 please explain briefly?
Saikumar said:
10 years ago
1600 = 0 odd days.
400 years = 0 odd days.
15 years will be remained.
15 year will have (3 leap years + 12 ordinary years).
= (3*2+1*12) = (6+12) = 18 = 7+7+4 = 4 odd days.
8 = 1 week+1 day.
(0+0+4+1) = 5 days = Friday.
400 years = 0 odd days.
15 years will be remained.
15 year will have (3 leap years + 12 ordinary years).
= (3*2+1*12) = (6+12) = 18 = 7+7+4 = 4 odd days.
8 = 1 week+1 day.
(0+0+4+1) = 5 days = Friday.
DATTA said:
10 years ago
2000 to 2010 having 10 years.
In which 3 leap year (2000-01), (2004-05), (2008-09) & 7 normal years.
3 leap years have 6 odd days (3 years * 2 odd days) = 6 odd day.
Remaining 7 year having 7 odd day (individually 1) & for year (2010-11).
January February March April May June July Aug.
(31 + 28 + 31 + 30 + 31 + 30 + 31 + 15) = 227 days.
No of odd day = 227/7 = Remainder is 3.
So total odd days are 3+6+7 = 16.
Now 16/7, remainder is 2.
So Tuesday will come.
So how answer will come (Sunday)?
In which 3 leap year (2000-01), (2004-05), (2008-09) & 7 normal years.
3 leap years have 6 odd days (3 years * 2 odd days) = 6 odd day.
Remaining 7 year having 7 odd day (individually 1) & for year (2010-11).
January February March April May June July Aug.
(31 + 28 + 31 + 30 + 31 + 30 + 31 + 15) = 227 days.
No of odd day = 227/7 = Remainder is 3.
So total odd days are 3+6+7 = 16.
Now 16/7, remainder is 2.
So Tuesday will come.
So how answer will come (Sunday)?
Vani said:
10 years ago
Instead of taking 2000 as reference can we take 2008 as it is also a leap year and closer to 2009?
Candy said:
9 years ago
I am not understand please say how will it come?
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