Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 2)
2.
What was the day of the week on 28th May, 2006?
Answer: Option
Explanation:
28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)
Odd days in 1600 years = 0
Odd days in 400 years = 0
5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) 
6 odd days
Jan. Feb. March April May (31 + 28 + 31 + 30 + 28 ) = 148 days
148 days = (21 weeks + 1 day) 1 odd day.
Total number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.
Given day is Sunday.
Discussion:
214 comments Page 20 of 22.
Sugu said:
7 years ago
@Deena.
Thank you a lot.
Thank you a lot.
Tony said:
7 years ago
Why not we take no of odd days in 2000 is 0? Anyone explain me.
Jhon said:
7 years ago
Why not adding 800 to 1600 and calculate it up to 2004?
Bikram said:
6 years ago
Is 2000 Leap year or ordinary year?
Bikram said:
6 years ago
The Correct answer is Monday.
Pushpa said:
6 years ago
Thanks for the answer.
Pushpa said:
6 years ago
Thanks @Bikramdevgan.
Ishwar choudhary said:
6 years ago
I think there should be (2000+6) year+jan Feb, Mar, April and 28 May. It gives 1 odd day and answer is Monday.
Rahul said:
6 years ago
How the total odd days is found? please explain.
Anomie said:
6 years ago
@Anilkumar.
Odd days are the remainder, not the quotient.
Odd days are the remainder, not the quotient.
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