Aptitude - Calendar - Discussion

@Deena.

I think it is 1990 instead of 1900.

Odd day means (it is the day after counting weeks. In a normal year, we consists of 52 weeks and 1 odd day and in leap year we consists 52 weeks and 2 odd days).

(28+06+1+6+(06/4) )/7 = 43/7 = 1.

Since to know what is the day of 28th may.

2000year+5year+may 28.

100 year = 5odd days, 2000 year = 5 * 20 = 100days + 5 days(400,800,1200,1600,2000),
105days = 15 week 0 odd days,
5 years =1+1+1+2+1=6 odd days,
may 28 =1 odd day.
1+6=7 days=1 week 0 odd days.

So it's Sunday.

Since to know what is the day of 28 th may.
2000 years+ 5year+ may 28.

100 year = 5odd days.
2000 year= 5 * 20 = 100days + 5 days(400,800,1200,1600,2000).
105days = 15weeks 0 odd days,
May 28 = 1 odd days.
1+6 = 7 days = 1week 0 odd days.

You can do this in easier way;

2000 Jan 1st is always Sunday so;
2000 Jan 1st Sunday
-2006 May 28
-------------------------------
6+1(leap year i.e. 2004) =7

Jan(31-1)=30 feb=28 march=31 April=30

May=28(as in the question we are asked to find the day of 28th May)
Now add all = 7+30+28+31+30+28 =154.

Now divide this number by 7 to find the odd day 154÷7 =22 as the remainder is zero so the day remains the same Sunday.

If the remainder was to suppose 2 then count two times after the Sunday because 2000 1st Jan is always Sunday which would have been Tuesday.
And for the 12 months for easy odd number counting.

Jan=31÷7=3
Feb=28÷7=0
March=31÷7=3
April=30÷7=2
May=31÷7=3
June=30÷7=2
July=31÷7=3
Aug=31÷7=3
Sept=30÷7=2
Oct=31÷7=3
Nov=30÷7=2
Dec=31÷7=3.

You can remember it as a formula (June Say No 2 April) these four have 2 odd numbers while others have 3 except February(i.e. 0).

Note:that Say is for September (Se) and No for November (No).

Thank you @Senthil. Very nice explanation. Now I understood properly.

Sorry if anyone has answered already I did not go through the solution.
Here goes the solution,

DAYS:-

0-S, 1-M, 2-T, 3-W, 4-TH, 5-F, 6-SAT

MONTH:-

[J F M][A M Ju][JuL A S][O N D]
[0 3 3] [6 1 4][ 6 2 5][0 3 5] // [ ] Just for simplicity

YEARS;-

1600 to 1699 consider code as 6
1700 to 1799 consider code as 4
1800 to 1899 consider code as 2
1900 to 1999 consider code as 0
2000 to 2099 consider code as 6

FOLLOW THE FOLLOWING STEPS:-

1) Take last two digits of given year: _ _
2) Divide the above taken number by 4 and consider the quotient: _ _
3) Take the date: _ _
4) Take the month: _ _
5) Choose the code of the year as specified above: _
6) Add everything and divide by 7 and consider the remainder the result will be from 0 to 7(any one number).

Match with the day that will be the result.

I am unable to understand. This same question is in fitjee entrance exam.

28 means 28/7... It means 0.
May code is 1.
Year 6.
Leap year 1.
Century code is. 6.
Therefore 0+1+6+1+6= 14/7. The remainder is 0.
0 is the code of Sunday.