Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 2)
2.
What was the day of the week on 28th May, 2006?
Answer: Option
Explanation:
28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)
Odd days in 1600 years = 0
Odd days in 400 years = 0
5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) 
6 odd days
Jan. Feb. March April May (31 + 28 + 31 + 30 + 28 ) = 148 days
148 days = (21 weeks + 1 day) 1 odd day.
Total number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.
Given day is Sunday.
Discussion:
214 comments Page 22 of 22.
Raj sharma said:
5 years ago
Learn that every 400 years odd days will be zero.
Akshay Chavda said:
5 years ago
Day --> +28
month code --> +2
year--> + 6
yr/4 --> +1
-----
37/7 = 2 odd days - 1 =1 .
It is Sunday.
month code --> +2
year--> + 6
yr/4 --> +1
-----
37/7 = 2 odd days - 1 =1 .
It is Sunday.
Sanjana said:
5 years ago
Why are 400 and 1600 yrs taken, why not other years? Please anyone explain me.
Narendra said:
5 years ago
How to take 400, 1600? Please anyone explain me.
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