Aptitude - Calendar - Discussion

In the formula type (2006-1990) is 106 only, answer comes when we substitute 106.

Please explain clearly bro I don't understand this problem.

Odd days in 1600 years = 0.

Odd days in 400 years = 0.

Why is it?

Anyone tell me,

What is the formula (0+0+6+1)?

I can't understand.

" if you remember this points you can solve the answer in 20 seconds only "

Month Codes:
(J F M A M J J A S O N D)
(0 3 3 6 1 4 6 2 5 0 3 5)
Year codes:

1600-1699 =>6
1700-1799 =>4
1800-1899 =>2
1900-1999 =>0 (repetition)
--------------------------------------------------
2000-2099 =>6
2100-2199 =>4
2200-2299 =>2
2300-2399 =>0

Week day=date+year(last two digits)+leap years+month code+year code.

What was the day of the week on 28th May, 2006?
28+06+01+1+6=46,
week day=46/7=0,
0 means Sunday.

@Deena.

Kindly help me to solve and find the day for 1 April 2001 using your tricks.

@Jyoti:

Remember 1 Jan 2018 As a Monday.
Now if a year increase or decrease, i.e- 1jan 2019 will Tuesday and 1jan 2017 was Sunday...
*Remember to increase or decrease 2days in leap year.

Now for 1 April 2001:-
As 1 Jan 2018 was Monday.
2018-2001 =17 yr in which 2004,2008,2012,2016 were comes as a leap yr. So totally we have to decrease my 21 ,i.e 21/7 completely divisible. So 1 Jan 2001 is also Monday.

As 1 jan 2001 as a Monday (30days in jan + 28 days in feb + 31days in march + 1Day in April)= 90,

90/7=6 as a remainder so,
1April 2001 is Sunday ..( Mon +6days).

If It is like that, Can anybody tell me what was the day on 1 Jan 1601 ?

When I calculate;

The 1600 year will have 0 odd days ( as it says 400 years has 0 odd days )
1 Jan i.e 1 odd day.
Total odd days till 1 Jan 1601 =1 odd day.
I.e. Monday ( As formula says 0 - Sunday, 1 - Monday ).

But the Actual day on 1 Jan 1601 was Thursday.

So, please explain me to get the solution.

What was the day of the week on 28th August 2016?

Please explain by this method.

100 years = 76 ordinary years + 24 leap years (is it not 25 leap years).