Aptitude - Calendar - Discussion

Discussion Forum : Calendar - General Questions (Q.No. 2)
2.
What was the day of the week on 28th May, 2006?
Thursday
Friday
Saturday
Sunday
Answer: Option
Explanation:

28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)

Odd days in 1600 years = 0

Odd days in 400 years = 0

5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) 6 odd days

Jan.  Feb.   March    April    May 
(31 +  28  +  31   +   30   +   28 ) = 148 days

148 days = (21 weeks + 1 day) 1 odd day.

Total number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.

Given day is Sunday.

Discussion:
214 comments Page 10 of 22.

Lateef Ansari said:   1 decade ago
I solved this problem this way.

step 1 : 28 may 2006: take date and year's last two digit number.

28+06 = 34.

step 2: year is divided by 4 so 06/4=1(leave the remainder).
step 3: Codes.

Jan : 0
Feb : 3
Mar : 3
aprl: 6
May : 1
Jun : 2
July; 6
aug : 2
Sep : 5
oct : 0
Nov : 3
Dec : 5

Now add step 1,step 2,step 3 ie,. 34+1+1=36.

divide it by seven 7, so remainder is 0.

Then,

0 = sunday.
1 = monday.
2 = tuesday.
3 = wednesday.
4 = thursday.
5 = friday.
6 = saturday.

Aman said:   1 decade ago
Odd days means when you divide by 7 to get the no of weeks the remainder left is known to be odd days.

Arun Anoop M said:   1 decade ago
I will give you one example:

--------------------------
First of all you have to learn imp things...ie;

Step 1:
Odd days in 100 years is 5
Odd days in 200 years is 3
Odd days in 300 years is 1
Odd days in 400 years is 0

---------------------------

Ok.

Step 2:

1 for Mon , 2 for Tue ..... 7 for sunday.

Step 3:

Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec
31 28 31 30 31 30 31 31 30 31 30 31

Step 4:

Example is

Find a day ?

From "28 May 2006"

2005 years + (01-01-2006 to 28-05-06)

CONVERT 2005 as

2005 is same as 1600+400+5

Odd days in 1600 years is 0
Odd days in 400 years is 0

Calculate 5years?

5years = (5/4)leap year + (5- (5/4)) ordinary day
= 1 leap year + 4 ordinary days
= (1*2) ordinary days + 4 ordinary days
= 6 odd days.

Next Step:

Jan+Feb+Mar+Apr+May=31+28+31+30+28=148 odd days.

Convert 148 as (weeks+days)format.

How?

148/7 = (21 weeks)+(1 odd day)
= 1 odd day.

Final Step:

1600+400+5+months+day = 0+0+6+1 = 7.

So DAY is SUNDAY.

Kaustubh said:   1 decade ago
How did 1600 and 400 come please explain me?

Tamil said:   1 decade ago
Total number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.

I don't get this step could anyone help me?

Komal said:   1 decade ago
Can someone please explain 'mathematically' the solution for this problem and not by codes. Thanks in advance.

Dechen said:   1 decade ago
Kindly can anyone of you share me why is odd day 1600 and 400 is taking in this problem please. I would be very grateful for your response :).

I m Zero said:   1 decade ago
@Dechen.

Simply we need to come till 2006 so,

Means 1600+400 = 2000.

Then remaining 2001, 2002, ....2006.

I m Zero said:   1 decade ago
@Dechen.

Hi.

28th may 2006.

So we need to calculate form.

1 jan 0001st year to 28th may 2006th year.

First 1600th yr dont have odd days rite means 1600/4 = 0 odd day.
400/4 = 0 odd day.

So we reach 1st jan 2000th year ok. Now 2001, 2002,.... 2006 28th may.

Bitupi said:   1 decade ago
I can't understand this problem. Please explain in simple. What is the odd no?


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