Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 2)
2.
What was the day of the week on 28th May, 2006?
Answer: Option
Explanation:
28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)
Odd days in 1600 years = 0
Odd days in 400 years = 0
5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) 
6 odd days
Jan. Feb. March April May (31 + 28 + 31 + 30 + 28 ) = 148 days
148 days = (21 weeks + 1 day) 1 odd day.
Total number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.
Given day is Sunday.
Discussion:
214 comments Page 11 of 22.
Naveen kumar said:
1 decade ago
Please explain one example with simple method?
Naveen kumar said:
1 decade ago
If in the last step I get "6" which day I consider, because you don't give no week day for "6".
Suresh said:
1 decade ago
Please explain why you consider 1600 is zero odd days?
Sanjeet said:
1 decade ago
@Vijay singh your answer is right and if you observe it carefully you will understand how 400 is having zero Odd days.
Kamal said:
1 decade ago
2004 have also 0 why did you not use by 2004?
Laila said:
1 decade ago
Keep year has 366 days so comparing to non keep year it has an extra day generally a non keep year has an odd day (non keep year has 365 days 364+1==365 so the last day is odd day) so keep year has 2 odd days.
Thiru said:
1 decade ago
6/4 = 1.3.
take 1,
Now, 1+28+6+1.
36.
36/7.
1.
Which is sunday.
take 1,
Now, 1+28+6+1.
36.
36/7.
1.
Which is sunday.
Charan said:
1 decade ago
What is mean by odd days I can't understand can you please explain it in brief?
Tina said:
1 decade ago
Hello @Thiru thanks for your explanation but could you please make it a bit clear so that we can understand better because from where you got the second calculation i.e 1+28+6+1 ?
Shanmukha said:
1 decade ago
How to calculate odd days in a year?
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