Aptitude - Calendar - Discussion

I can't understand this step plz explain it?? 5=(5/4)leap yr+[5-1]ordinary day
=1 leap year+4 ordinary day

Why there is 1900 in above mentioned explanation?

How can we say 0 is sunday 1 is monday, 2 tues day, . How can we know the jan 1st 2006 week day?

How can we say the odd day is 0 for 1600 and 400 years...i am getting 1 odd day for total 2000 years....hear is my calculation if wrong pls corret it..

2000/4=500
so 500 leap years..no of odd days for 500 years is (500*2)1000
and 1500 ordinary years having 1500 odd days
total=1500+1000=2500
no of odd days in these 2500 days: 2500/7 = 1 odd day

is it correct procedure?

Solution: JFM AMJ JAS OND
1. Choose appropriate month code: 602 503 514 624
2. Leap years since 1/1/2000 (including the year 2000):
3. Add the month code from step 1, the number of leap years, the day of the month, and the amt of years since 2000. Divide this by 7 and take the remainder.
4. Sun = 1, Mon= 2, T = 3...Fri=6, Sat=0,7

Example: January 1,2050
1. month code 6 2. 50yrs/4=12r2. 12+1 (since Feb 2000 had a leap day) = 13
3. 6 + 13 + 1 + 50 = 70. 70/7=10r0
4. remainder of 0 -> January 1, 2050 will be a Saturday

*If the year you are calculating is a leap year and the date is BEFORE February 29, do add the 1*
Example of this: February 18, 2008
1. month code 2
2. 2 (Feb 2000 & 2004 BUT NOT 2008 yet)
3. 2 + 2 + 18 + 8 = 30. 30/7=4r2
4. remainder 2 -> Monday

Deena your wrong by the way gave some idea to do calender sum like this thank you.

Naveen your procedure is absolutely prefect and thanks boss.

The fast and easy solution according to me is like this:

Days code:- S=1,M=2,T=3,W=4,TH=5,F=6,S=7/0
Month code
JFM AMJ JAS OND
144 025 036 146

CENTURY CODE
100/ 200/ 300/ 400
500 /600/700/ 800

--------------------
4 / 2 / 0 / 6

Ex. 15/8/1947 = day ?
Sol: date+month code+ century code + leap year days + normal year days= odd days/7
15+3 + 0 +11*2 + 36 = 76/7, odd days = 6 by matching odd days, it is FRIDAY

Guyz we always calculate from 31st DEC 200.. to 31 st DEC 200..

So here, 31 st DEC 2000 to 31st DEC 2005 we gonna calculate

Now year 2001, odd days => 1
2002 => 1
2003 => 1
2004 => 2
2005 => 1

6 odd days and rest of the calculation you can see above.

Too many different month codes used to do the calculation in the above answer figures !

Odd days= (that particular year) /7, the remainder that you get is the no.of odd days in it.