Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 3)
3.
What was the day of the week on 17th June, 1998?
Answer: Option
Explanation:
17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)
Odd days in 1600 years = 0
Odd days in 300 years = (5 x 3) 
1
97 years has 24 leap years + 73 ordinary years.
Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.
Jan. Feb. March April May June (31 + 28 + 31 + 30 + 31 + 17) = 168 days
168 days = 24 weeks = 0 odd day.
Total number of odd days = (0 + 1 + 2 + 0) = 3.
Given day is Wednesday.
Discussion:
165 comments Page 15 of 17.
Sharath said:
6 years ago
400 years = (5 x 4 + 1).
Here 1 is added because of leap year !
Here 1 is added because of leap year !
Yashu said:
6 years ago
Anyone tell why we consider 300 & 1600 years only. Why don't we consider 400 or other than that?
Shweta said:
6 years ago
Thank you @Arya, @Inshan, @Nitesh.
(1)
Kirtan said:
6 years ago
How many leap years are there between1701 and 1900 (both included) ?
Dream boy said:
6 years ago
How to know a day of a particular date?
Dream boy said:
6 years ago
How to know a day of a particular date?
Kavi said:
6 years ago
Which day of 21 July 1997. Describe below.
Sound said:
6 years ago
Why do we take that 1600 and 300?
Binudass said:
5 years ago
How can I calculate the no of odd days in 100 years? Please, anyone, tell me.
Shagun pachisia said:
5 years ago
How we calculate no of leap years in 97 years? Please explain me.
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