Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 3)
3.
What was the day of the week on 17th June, 1998?
Answer: Option
Explanation:
17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)
Odd days in 1600 years = 0
Odd days in 300 years = (5 x 3) 1
97 years has 24 leap years + 73 ordinary years.
Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.
Jan. Feb. March April May June (31 + 28 + 31 + 30 + 31 + 17) = 168 days
168 days = 24 weeks = 0 odd day.
Total number of odd days = (0 + 1 + 2 + 0) = 3.
Given day is Wednesday.
Discussion:
165 comments Page 16 of 17.
Jala said:
5 years ago
98 is a leap year then February has 29 days right?
Shikare said:
5 years ago
Why we took 300 years?
(1)
Suba said:
4 years ago
Could anyone explain me why are we considering 300 years? .
(2)
Pratyush Singh said:
4 years ago
96/4 = 24. and 96 -24 =72 ordinary years.
This means in 96 years there are 24 leap years and 72 ordinary years.
So, in 97 years = 96 (24 odd +72 ordinary)+ 1 (ordinary).
=> 97 years = 24 odd + 73 ordinary years.
i.e. 97-24 = 73 ordinary years.
This means in 96 years there are 24 leap years and 72 ordinary years.
So, in 97 years = 96 (24 odd +72 ordinary)+ 1 (ordinary).
=> 97 years = 24 odd + 73 ordinary years.
i.e. 97-24 = 73 ordinary years.
(4)
Aman said:
4 years ago
Hi,
I don't understand about 1600 and 300 years, please explain.
I don't understand about 1600 and 300 years, please explain.
(8)
Ananthu SV said:
4 years ago
@All.
Just remember;
100yrs --> 5 odd
200yrs --> 3 odd
300yrs --> 1odd
400yrs --> 0 odd
Now given 1998 jun 17:
We can write 1600 + 300 + 97 + jan1 to june 17
1600 because it gives odd days as 0 because its a multiple of 400.
300 because you know the odd days is 1 from the above table,
Remaining 97 yrs and jan1 to jun17.
For 97yrs -> 24 leap year and 73 ordinary years.
To calculate the odd days.
For all leap year, multiply by 2 and for an ordinary year with 1.
So,24 * 2 + 73*1 = 121.
Now 121/7 = remainder 2 (odd days)
Therefore;
1600 -> 0 odd days,
300 -> 1 odd days,
97 -> 2 odd days.
Jan 1 to jun17 -> we have 3 (31 days), 1 (30 day), 1 (28 day), and 17 days.
Remember:
31days->3,
30days->2,
29->1.
28->0.
So, we get 3 * 3 + 1 * 2 + 1 * 0 + 17 = 9+2+17 = 28 odd days.
For final step:
0 + 1 + 2 + 28 = 31,
31/7=3 remainder.
Chart:
Sun - 0,
Mon - 1,
Tue - 2,
Wed - 3,
Thu - 4,
Fri - 5,
Sat - 6.
So 3 in the chart is *WEDNESDAY*.
Just remember;
100yrs --> 5 odd
200yrs --> 3 odd
300yrs --> 1odd
400yrs --> 0 odd
Now given 1998 jun 17:
We can write 1600 + 300 + 97 + jan1 to june 17
1600 because it gives odd days as 0 because its a multiple of 400.
300 because you know the odd days is 1 from the above table,
Remaining 97 yrs and jan1 to jun17.
For 97yrs -> 24 leap year and 73 ordinary years.
To calculate the odd days.
For all leap year, multiply by 2 and for an ordinary year with 1.
So,24 * 2 + 73*1 = 121.
Now 121/7 = remainder 2 (odd days)
Therefore;
1600 -> 0 odd days,
300 -> 1 odd days,
97 -> 2 odd days.
Jan 1 to jun17 -> we have 3 (31 days), 1 (30 day), 1 (28 day), and 17 days.
Remember:
31days->3,
30days->2,
29->1.
28->0.
So, we get 3 * 3 + 1 * 2 + 1 * 0 + 17 = 9+2+17 = 28 odd days.
For final step:
0 + 1 + 2 + 28 = 31,
31/7=3 remainder.
Chart:
Sun - 0,
Mon - 1,
Tue - 2,
Wed - 3,
Thu - 4,
Fri - 5,
Sat - 6.
So 3 in the chart is *WEDNESDAY*.
(48)
Vani Arora said:
3 years ago
I cannot get the answer. Anyone help me to get the answer clearly.
(8)
Ali said:
3 years ago
Instead of going straight forward from 1600 then 1900 then to 1997 can we come reverse from 2000 to 1998?
Is it possible? Anyone, clarify it.
Is it possible? Anyone, clarify it.
(7)
Shanthi said:
3 years ago
You are right, thanks @Sri Harsha.
(4)
Zafar Ali said:
3 years ago
The output of = years (date (2016, 5, 1), date (2013, 5, 1), 0) will return.
(3)
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