Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 3)
3.
What was the day of the week on 17th June, 1998?
Answer: Option
Explanation:
17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)
Odd days in 1600 years = 0
Odd days in 300 years = (5 x 3) 
1
97 years has 24 leap years + 73 ordinary years.
Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.
Jan. Feb. March April May June (31 + 28 + 31 + 30 + 31 + 17) = 168 days
168 days = 24 weeks = 0 odd day.
Total number of odd days = (0 + 1 + 2 + 0) = 3.
Given day is Wednesday.
Discussion:
165 comments Page 1 of 17.
Yadagiri said:
2 years ago
The last digit of the year = 98.
Quotient when divisible by 4 = 24.
Day in the given date = 17.
Digit of the month = 4.
Digit of the year = 0.
Add all these you will get = 143*7.
You will get the remainder as 3.
Then the above day is Wednesday.
Quotient when divisible by 4 = 24.
Day in the given date = 17.
Digit of the month = 4.
Digit of the year = 0.
Add all these you will get = 143*7.
You will get the remainder as 3.
Then the above day is Wednesday.
(32)
Deekshitha said:
2 years ago
How we can find odd days? Anyone, please help me to get this?
(9)
Tim said:
2 years ago
Considering our question we have 97 complete years ie (1901- 1997) , leaving 1998, 1999, and 2000 to complete the century. One of the rules says that every 4th century is a leap year, which implies 2000 is a leap year.
So, why do we have 24 leap years and 73 ordinary years in the 97 years instead of 23 leap years and 74 ordinary years since 2000 is a leap year?
So, why do we have 24 leap years and 73 ordinary years in the 97 years instead of 23 leap years and 74 ordinary years since 2000 is a leap year?
(13)
Raza said:
2 years ago
Here, 17 + 5 + 98 + 24 = 144/7 = remainder 4 {wednesday].
(12)
Hemanad sagaria said:
3 years ago
Formula = date+ year+quaten+monthy code+year code/7.
= 17 + 98 + 24 + 4 + 0/7,
= 143/7.
= reminder is 3 then date code is 3 = Wednesday.
Then 98/4= 24.5.
= 17 + 98 + 24 + 4 + 0/7,
= 143/7.
= reminder is 3 then date code is 3 = Wednesday.
Then 98/4= 24.5.
(23)
Zafar Ali said:
3 years ago
The output of = years (date (2016, 5, 1), date (2013, 5, 1), 0) will return.
(3)
Shanthi said:
3 years ago
You are right, thanks @Sri Harsha.
(4)
Ali said:
3 years ago
Instead of going straight forward from 1600 then 1900 then to 1997 can we come reverse from 2000 to 1998?
Is it possible? Anyone, clarify it.
Is it possible? Anyone, clarify it.
(7)
Vani Arora said:
3 years ago
I cannot get the answer. Anyone help me to get the answer clearly.
(8)
Ananthu SV said:
4 years ago
@All.
Just remember;
100yrs --> 5 odd
200yrs --> 3 odd
300yrs --> 1odd
400yrs --> 0 odd
Now given 1998 jun 17:
We can write 1600 + 300 + 97 + jan1 to june 17
1600 because it gives odd days as 0 because its a multiple of 400.
300 because you know the odd days is 1 from the above table,
Remaining 97 yrs and jan1 to jun17.
For 97yrs -> 24 leap year and 73 ordinary years.
To calculate the odd days.
For all leap year, multiply by 2 and for an ordinary year with 1.
So,24 * 2 + 73*1 = 121.
Now 121/7 = remainder 2 (odd days)
Therefore;
1600 -> 0 odd days,
300 -> 1 odd days,
97 -> 2 odd days.
Jan 1 to jun17 -> we have 3 (31 days), 1 (30 day), 1 (28 day), and 17 days.
Remember:
31days->3,
30days->2,
29->1.
28->0.
So, we get 3 * 3 + 1 * 2 + 1 * 0 + 17 = 9+2+17 = 28 odd days.
For final step:
0 + 1 + 2 + 28 = 31,
31/7=3 remainder.
Chart:
Sun - 0,
Mon - 1,
Tue - 2,
Wed - 3,
Thu - 4,
Fri - 5,
Sat - 6.
So 3 in the chart is *WEDNESDAY*.
Just remember;
100yrs --> 5 odd
200yrs --> 3 odd
300yrs --> 1odd
400yrs --> 0 odd
Now given 1998 jun 17:
We can write 1600 + 300 + 97 + jan1 to june 17
1600 because it gives odd days as 0 because its a multiple of 400.
300 because you know the odd days is 1 from the above table,
Remaining 97 yrs and jan1 to jun17.
For 97yrs -> 24 leap year and 73 ordinary years.
To calculate the odd days.
For all leap year, multiply by 2 and for an ordinary year with 1.
So,24 * 2 + 73*1 = 121.
Now 121/7 = remainder 2 (odd days)
Therefore;
1600 -> 0 odd days,
300 -> 1 odd days,
97 -> 2 odd days.
Jan 1 to jun17 -> we have 3 (31 days), 1 (30 day), 1 (28 day), and 17 days.
Remember:
31days->3,
30days->2,
29->1.
28->0.
So, we get 3 * 3 + 1 * 2 + 1 * 0 + 17 = 9+2+17 = 28 odd days.
For final step:
0 + 1 + 2 + 28 = 31,
31/7=3 remainder.
Chart:
Sun - 0,
Mon - 1,
Tue - 2,
Wed - 3,
Thu - 4,
Fri - 5,
Sat - 6.
So 3 in the chart is *WEDNESDAY*.
(48)
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