Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 3)
3.
What was the day of the week on 17th June, 1998?
Answer: Option
Explanation:
17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)
Odd days in 1600 years = 0
Odd days in 300 years = (5 x 3) 
1
97 years has 24 leap years + 73 ordinary years.
Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.
Jan. Feb. March April May June (31 + 28 + 31 + 30 + 31 + 17) = 168 days
168 days = 24 weeks = 0 odd day.
Total number of odd days = (0 + 1 + 2 + 0) = 3.
Given day is Wednesday.
Discussion:
165 comments Page 2 of 17.
Aman said:
4 years ago
Hi,
I don't understand about 1600 and 300 years, please explain.
I don't understand about 1600 and 300 years, please explain.
(8)
Pratyush Singh said:
4 years ago
96/4 = 24. and 96 -24 =72 ordinary years.
This means in 96 years there are 24 leap years and 72 ordinary years.
So, in 97 years = 96 (24 odd +72 ordinary)+ 1 (ordinary).
=> 97 years = 24 odd + 73 ordinary years.
i.e. 97-24 = 73 ordinary years.
This means in 96 years there are 24 leap years and 72 ordinary years.
So, in 97 years = 96 (24 odd +72 ordinary)+ 1 (ordinary).
=> 97 years = 24 odd + 73 ordinary years.
i.e. 97-24 = 73 ordinary years.
(4)
Suba said:
4 years ago
Could anyone explain me why are we considering 300 years? .
(2)
Shikare said:
5 years ago
Why we took 300 years?
(1)
Jala said:
5 years ago
98 is a leap year then February has 29 days right?
Shagun pachisia said:
5 years ago
How we calculate no of leap years in 97 years? Please explain me.
Binudass said:
5 years ago
How can I calculate the no of odd days in 100 years? Please, anyone, tell me.
Sound said:
6 years ago
Why do we take that 1600 and 300?
Kavi said:
6 years ago
Which day of 21 July 1997. Describe below.
Dream boy said:
6 years ago
How to know a day of a particular date?
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers