Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 3)
3.
What was the day of the week on 17th June, 1998?
Answer: Option
Explanation:
17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)
Odd days in 1600 years = 0
Odd days in 300 years = (5 x 3) 
1
97 years has 24 leap years + 73 ordinary years.
Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.
Jan. Feb. March April May June (31 + 28 + 31 + 30 + 31 + 17) = 168 days
168 days = 24 weeks = 0 odd day.
Total number of odd days = (0 + 1 + 2 + 0) = 3.
Given day is Wednesday.
Discussion:
165 comments Page 17 of 17.
Hemanad sagaria said:
3 years ago
Formula = date+ year+quaten+monthy code+year code/7.
= 17 + 98 + 24 + 4 + 0/7,
= 143/7.
= reminder is 3 then date code is 3 = Wednesday.
Then 98/4= 24.5.
= 17 + 98 + 24 + 4 + 0/7,
= 143/7.
= reminder is 3 then date code is 3 = Wednesday.
Then 98/4= 24.5.
(23)
Raza said:
2 years ago
Here, 17 + 5 + 98 + 24 = 144/7 = remainder 4 {wednesday].
(12)
Tim said:
2 years ago
Considering our question we have 97 complete years ie (1901- 1997) , leaving 1998, 1999, and 2000 to complete the century. One of the rules says that every 4th century is a leap year, which implies 2000 is a leap year.
So, why do we have 24 leap years and 73 ordinary years in the 97 years instead of 23 leap years and 74 ordinary years since 2000 is a leap year?
So, why do we have 24 leap years and 73 ordinary years in the 97 years instead of 23 leap years and 74 ordinary years since 2000 is a leap year?
(13)
Deekshitha said:
2 years ago
How we can find odd days? Anyone, please help me to get this?
(9)
Yadagiri said:
2 years ago
The last digit of the year = 98.
Quotient when divisible by 4 = 24.
Day in the given date = 17.
Digit of the month = 4.
Digit of the year = 0.
Add all these you will get = 143*7.
You will get the remainder as 3.
Then the above day is Wednesday.
Quotient when divisible by 4 = 24.
Day in the given date = 17.
Digit of the month = 4.
Digit of the year = 0.
Add all these you will get = 143*7.
You will get the remainder as 3.
Then the above day is Wednesday.
(32)
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