Aptitude - Calendar - Discussion

Thanks for your answer @Sri Harsha.

Why should we take 1600 and 300 here? Please explain.

@Rajesh.

Can you please explain how get the year code.

1600 + 300 + 97 + (J to March)+17.

0 + 1 + {24(leap year)+73(ordinary y)}+(3+0+3+2+3) + 17.
1 + (24 * 2 + 73 * 1) + 17.
150/7.
21 week + 4 odd days.
Then the Ans is Thursday.

Take 1996 is a leap yera so it has 2 odd days.

Then 1997 has 1 odd day so total odd day till 1997 is;
(2+1)= 3.

Then,
Add the date till 01-01-1998 to 17- 06- 1997 so the total,
The day is 168 days divided it by 7, 168%7 = 0 odd days so total odd says from 1996 to 17-06-1998 is 3 only do that the day is WEDNESDAY.

@Akshay.

1st year to 10th year= 2 Leap year(LY) + 8 ordinary year(OY)
11th to 20th= 3 LY+7 OY.
21st to 30th= 2 LY+ 8 OY.
31st to 40th= 3 LY+ 7 OY.
41st to 50th= 2 LY+ 8 OY.
51st to 60th= 3 LY+ 7 OY.
61st to 70th= 2 LY+ 8 OY.
1st to 80th= 3 LY+ 7 OY.
81st to 90th= 2LY + 8 OY.
91st to 100th year= 3 LY+ 7 OY.

In total 25 leap year and 75 ordinary years in 100 years. Here we don't count 1st year as leap year. We've counted 1st year as OY.


Then how 24 LY + 76 OY in 100 year? Please explain to me.

Here, for calculation of 1997, they have said 1600 yrs + 300 yrs.

So the odd day obtained is 1. But instead, if we do 1700 yrs + 200 yrs than odd days obtained will be different. How to understand this? Please explain to me.

@All.

First we need to know about century codes;
1600-1699=6
1700-1799=4
1800-1899=2
1900-1999=0
2000-2999=6

Then we need to know month codes.

jan =0,feb=3, mar=3, apr=6, may=1, jun=4, july=6, aug=2, spt=5, oct=0, nvm=3, dec=5 afterv knowing this..
The finding procedure is;
Given date=28
Last two digits of the year=06
Last two digits divided by 4=1(taking the only quotient)
Century code =6.

AFTER, ADD ALL THE VALUES WE GET 42 SINCE WE HAVE 7 DAYS DIVIDE THE NUMBER 42/7=0.
Answer is SUNDAY.

How we got 5*3? Please tell me.

Thanks for the clear explanation @Prabhu.