Aptitude - Calendar - Discussion

The tricks say;

Find the difference of year 2007-2006 = 1.
And no of leap year between this two year is zero then,
0+1=1.
Then,
Saturday + 1 day = Sunday.

Step1:No.of odd days 2000=0.
Step2:No.of odd days 2001 to 2005=2+4=6.
Step3: No.of odd days-jan to Dec-8=342 (48 weeks+6 days=6.

Total No.of odd days=0+6+6=12/7=5 odd days 5 odd number is Friday. The answer is Friday.

How come it has 1 odd day?

Anyone please explain.

When we should subtract when should add, I'm not getting.

Can anyone explain me why we are subtracting when it says beyond 1? And in another q when it says beyond they are adding.

Anyone could tell me why we are not considering 2007's odd day, why only 2006's odd day Is considered?

After noticing many questions & problems based on this type. I finally observed these 2 key points which are:

1) We Subtract the day(s) number(odd or even) when we are asked in backward similarly.

2) We Add the the day(s)number(odd or even) when we are asked in forward.

eg:- For this question it was asked 8th dec 2006 providing 8th dec 2007.

Here goes the procedure:

Since neither 2006 nor 2007 is leap, we have ONE odd day.

As we are asked the day just subtract that ONE from the day given.

Implies we get Saturday-1=FRIDAY & that was the answer.

Every year divisible by 4 is a leap year. In your case 2006 is not divisible by 4, so it is not a leap year, hence it is an ordinary year.

One more thing is that; no century is a leap year...for example : 100, 200, 300, 500, 600, 700 and so on.......But every fourth century is a leap year...for example : 400, 800, 1200, 1600, 2000 so on.........

Please go through the formulas from the following link :

http://www.indiabix.com/aptitude/calendar/formulas

Cheerio!!

Why we say 2006 is the ordinary year. Plese tel me.

I don't know that.

Superb mannu.