Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 13)
13.
On 8th Dec, 2007 Saturday falls. What day of the week was it on 8th Dec, 2006?
Answer: Option
Explanation:
The year 2006 is an ordinary year. So, it has 1 odd day.
So, the day on 8th Dec, 2007 will be 1 day beyond the day on 8th Dec, 2006.
But, 8th Dec, 2007 is Saturday.
8th Dec, 2006 is Friday.
Discussion:
14 comments Page 1 of 2.
Purna said:
2 years ago
Anyone could tell me why we are not considering 2007's odd day, why only 2006's odd day Is considered?
(1)
Suzu said:
4 years ago
Can anyone explain me why we are subtracting when it says beyond 1? And in another q when it says beyond they are adding.
(2)
Bmh said:
5 years ago
When we should subtract when should add, I'm not getting.
(2)
Megha said:
6 years ago
How come it has 1 odd day?
Anyone please explain.
Anyone please explain.
(2)
Ravi said:
7 years ago
Step1:No.of odd days 2000=0.
Step2:No.of odd days 2001 to 2005=2+4=6.
Step3: No.of odd days-jan to Dec-8=342 (48 weeks+6 days=6.
Total No.of odd days=0+6+6=12/7=5 odd days 5 odd number is Friday. The answer is Friday.
Step2:No.of odd days 2001 to 2005=2+4=6.
Step3: No.of odd days-jan to Dec-8=342 (48 weeks+6 days=6.
Total No.of odd days=0+6+6=12/7=5 odd days 5 odd number is Friday. The answer is Friday.
(3)
Shaikh aasif said:
8 years ago
The tricks say;
Find the difference of year 2007-2006 = 1.
And no of leap year between this two year is zero then,
0+1=1.
Then,
Saturday + 1 day = Sunday.
Find the difference of year 2007-2006 = 1.
And no of leap year between this two year is zero then,
0+1=1.
Then,
Saturday + 1 day = Sunday.
(4)
Rithika said:
8 years ago
Hi friends!
Does it is necessary the question should be like from "8 DEC" 2001 TO "8DEC" 2005?
Can the question be like "8 dec"2001 to "10 dec" 2005?
Does it is necessary the question should be like from "8 DEC" 2001 TO "8DEC" 2005?
Can the question be like "8 dec"2001 to "10 dec" 2005?
Kalyan said:
10 years ago
Please explain how come 1 odd day?
Jagbir singh said:
1 decade ago
There will be 2 odd days in 8 december 2006 to 31 december 2006.
31-8 = 23/7 = remainder = 2.
How there will be 1 odd days?
31-8 = 23/7 = remainder = 2.
How there will be 1 odd days?
Sailesh said:
1 decade ago
After noticing many questions & problems based on this type. I finally observed these 2 key points which are:
1) We Subtract the day(s) number(odd or even) when we are asked in backward similarly.
2) We Add the the day(s)number(odd or even) when we are asked in forward.
eg:- For this question it was asked 8th dec 2006 providing 8th dec 2007.
Here goes the procedure:
Since neither 2006 nor 2007 is leap, we have ONE odd day.
As we are asked the day just subtract that ONE from the day given.
Implies we get Saturday-1=FRIDAY & that was the answer.
1) We Subtract the day(s) number(odd or even) when we are asked in backward similarly.
2) We Add the the day(s)number(odd or even) when we are asked in forward.
eg:- For this question it was asked 8th dec 2006 providing 8th dec 2007.
Here goes the procedure:
Since neither 2006 nor 2007 is leap, we have ONE odd day.
As we are asked the day just subtract that ONE from the day given.
Implies we get Saturday-1=FRIDAY & that was the answer.
(2)
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