Aptitude - Calendar - Discussion

Why we say 2006 is the ordinary year. Plese tel me.

I don't know that.

Every year divisible by 4 is a leap year. In your case 2006 is not divisible by 4, so it is not a leap year, hence it is an ordinary year.

One more thing is that; no century is a leap year...for example : 100, 200, 300, 500, 600, 700 and so on.......But every fourth century is a leap year...for example : 400, 800, 1200, 1600, 2000 so on.........

Please go through the formulas from the following link :

http://www.indiabix.com/aptitude/calendar/formulas

Cheerio!!

Superb mannu.

Why did we go back by one day? And not forward?

From saturday-> friday. Can't we go to sunday?

After noticing many questions & problems based on this type. I finally observed these 2 key points which are:

1) We Subtract the day(s) number(odd or even) when we are asked in backward similarly.

2) We Add the the day(s)number(odd or even) when we are asked in forward.

eg:- For this question it was asked 8th dec 2006 providing 8th dec 2007.

Here goes the procedure:

Since neither 2006 nor 2007 is leap, we have ONE odd day.

As we are asked the day just subtract that ONE from the day given.

Implies we get Saturday-1=FRIDAY & that was the answer.

There will be 2 odd days in 8 december 2006 to 31 december 2006.

31-8 = 23/7 = remainder = 2.

How there will be 1 odd days?

Please explain how come 1 odd day?

Hi friends!

Does it is necessary the question should be like from "8 DEC" 2001 TO "8DEC" 2005?

Can the question be like "8 dec"2001 to "10 dec" 2005?

The tricks say;

Find the difference of year 2007-2006 = 1.
And no of leap year between this two year is zero then,
0+1=1.
Then,
Saturday + 1 day = Sunday.

Step1:No.of odd days 2000=0.
Step2:No.of odd days 2001 to 2005=2+4=6.
Step3: No.of odd days-jan to Dec-8=342 (48 weeks+6 days=6.

Total No.of odd days=0+6+6=12/7=5 odd days 5 odd number is Friday. The answer is Friday.