Aptitude - Average - Discussion

Discussion Forum : Average - General Questions (Q.No. 8)
8.
The average age of husband, wife and their child 3 years ago was 27 years and that of wife and the child 5 years ago was 20 years. The present age of the husband is:
35 years
40 years
50 years
None of these
Answer: Option
Explanation:

Sum of the present ages of husband, wife and child = (27 x 3 + 3 x 3) years = 90 years.

Sum of the present ages of wife and child = (20 x 2 + 5 x 2) years = 50 years.

Husband's present age = (90 - 50) years = 40 years.

Discussion:
101 comments Page 7 of 11.

Karthick said:   9 years ago
Average = sum/no of count.

27 = h + w + c/3.
h + w + c = 81.
20 = w + c - 1/2.
w + c = 41.
h + 41 = 81.

H = 40.
(1)

Kanchan shah said:   7 years ago
27*3=81,
81+9=90,
5year ago =formula( average age*2),
So, 20*2=40,
40+10=50.
Husband age 90 - 50 = 40.

John Smith said:   1 decade ago
Present age of h+w+c = (27+3)*3 = 90.

Present age of w+c = (20+5)*2 = 50.

h's age = 90-50 = 40.
(1)

Manoj Kumar said:   5 years ago
@Varshithtunuguntla.

How obtained here 90 and 40. How did the multiplication?

Can you tell me?
(3)

Mahesh said:   1 decade ago
h+w+c/3 = 27.
h+w+c = 81.

w+c/2 = 20.
w+c = 40.

h+w+c = 81.

h+40 = 81.

h = 81-40.

h = 40.

Gopalkrishna said:   1 decade ago
Present age:

H+W+C=30*3.
W+C=25*2.
....................
ie...,H=40 year.

Guhan said:   9 years ago
Ramya it is very easy to understand. Keep solving the problem in the easiest way.

Mayuri khode said:   5 years ago
@Bharani.
Instead of addition W+C you can replace it by H+C.
i.e (H+W+C)-(H+C).

Priya said:   1 decade ago
((h-3)+(w-3)+(c-3))/3=27
h+w+c=90.
how to 90 comes ? I don't understand.

Yasir Aziz said:   8 years ago
@Naseem.

You gave the easy and best solution for this question. Thanks.


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