Aptitude - Average - Discussion
Discussion Forum : Average - General Questions (Q.No. 8)
8.
The average age of husband, wife and their child 3 years ago was 27 years and that of wife and the child 5 years ago was 20 years. The present age of the husband is:
Answer: Option
Explanation:
Sum of the present ages of husband, wife and child = (27 x 3 + 3 x 3) years = 90 years.
Sum of the present ages of wife and child = (20 x 2 + 5 x 2) years = 50 years.
Husband's present age = (90 - 50) years = 40 years.
Discussion:
101 comments Page 5 of 11.
Ahmedshaonaiub said:
9 years ago
5 years age child and wife Avg age was 20, so 3 years ago it was 22.
There we find (27 * 3) - (22 + 22) = 37; 37 is the husbands age 3 years ago,
So present year age => 37 + 3 = 40.
There we find (27 * 3) - (22 + 22) = 37; 37 is the husbands age 3 years ago,
So present year age => 37 + 3 = 40.
Prakhar Malviya said:
8 years ago
The presnet ages of 3 three.
(x+y+z)/3=30 ---> eq1.
Five years ago
(y+z)/2=25
y+z=50 ---> eq.2.
Put the values of y+z in thr first equation we get:-
(x+50)/3=30,
x=90-50,
x=40.
(x+y+z)/3=30 ---> eq1.
Five years ago
(y+z)/2=25
y+z=50 ---> eq.2.
Put the values of y+z in thr first equation we get:-
(x+50)/3=30,
x=90-50,
x=40.
Karthy said:
1 decade ago
When the solution is started like this
husband=x,wife=y&child=z
bf4 3yrs x-3+y-3+z-3/3 =27
terefore x+y+z=90--1
bf4 5yrs y-5+z-5/2 =20
terefore y+z=50---2 (1-2)
terefore x=40
husband=x,wife=y&child=z
bf4 3yrs x-3+y-3+z-3/3 =27
terefore x+y+z=90--1
bf4 5yrs y-5+z-5/2 =20
terefore y+z=50---2 (1-2)
terefore x=40
Srihari said:
2 years ago
H + W + C = 27 + 3 = 30(3 years),
H + W + C = 30 * 3 = 90 (3 persons),
W + C = 20 + 5 =25(5 years),
W + C = 25 * 2 = 50(2 persons),
H + W + C - W + C = H.
90 - 50 = 40years.
H + W + C = 30 * 3 = 90 (3 persons),
W + C = 20 + 5 =25(5 years),
W + C = 25 * 2 = 50(2 persons),
H + W + C - W + C = H.
90 - 50 = 40years.
(34)
Himanshu arora said:
7 years ago
3 year ago(h+w+c) = 27 * 3 = 81.
5 year ago=81-6 = 75(2h+2w+2c).
5 year ago(w+c) = 2 * 20 = 40.
5 year ago h = 75-40 = 35.
And the present age is 40 years of the husband.
5 year ago=81-6 = 75(2h+2w+2c).
5 year ago(w+c) = 2 * 20 = 40.
5 year ago h = 75-40 = 35.
And the present age is 40 years of the husband.
Kavi said:
8 years ago
Please clarify my doubt. If my age is 10 before 3 years then at present my age should be 13. So it is (10+3) not (10-3) right. But why we subtracted 3 in above question?
Loverboy said:
1 decade ago
3 years ago,their avg is 27.
((h-3)+(w-3)+(c-3))/3=27
h+w+c=90.(present)
5 years ago w & c is 20.
((w-5)+(c-5))/2=20
w+c=50.(present)
(h+w+c)-(w+c)=40.
h=40 years
((h-3)+(w-3)+(c-3))/3=27
h+w+c=90.(present)
5 years ago w & c is 20.
((w-5)+(c-5))/2=20
w+c=50.(present)
(h+w+c)-(w+c)=40.
h=40 years
Akki said:
7 years ago
Fathers age is the sum of mother and his son age but the today's average age of three of them are 20 so what will be the today's age of father? Can anyone solve this?
Praveen said:
1 decade ago
@vinod ..
h+w+c - w+c =husbands age
27*3 here 27 is average age and 3 is the number (sum is avg*n )
and 3*3 here we are taking after 3 years and into(*) 3 munbers.
h+w+c - w+c =husbands age
27*3 here 27 is average age and 3 is the number (sum is avg*n )
and 3*3 here we are taking after 3 years and into(*) 3 munbers.
Kalyan said:
8 years ago
In the year 1950 the avg. Of 6 brothers is 15 years.The youngest brother died in 1957 at the age of 12 years.find the avg. Remaining in 1958?
Can anyone solve this?
Can anyone solve this?
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