Aptitude - Average - Discussion

Discussion Forum : Average - General Questions (Q.No. 8)
8.
The average age of husband, wife and their child 3 years ago was 27 years and that of wife and the child 5 years ago was 20 years. The present age of the husband is:
35 years
40 years
50 years
None of these
Answer: Option
Explanation:

Sum of the present ages of husband, wife and child = (27 x 3 + 3 x 3) years = 90 years.

Sum of the present ages of wife and child = (20 x 2 + 5 x 2) years = 50 years.

Husband's present age = (90 - 50) years = 40 years.

Discussion:
101 comments Page 4 of 11.

Shah said:   1 decade ago
(3x27)+3 [ 27 is avg. age x 3 family members + 3( ie number years ago) ... Ans comes to 85 years.
(2x20)+5 [ 20 is avg. age of child and mother x 2 + 5( ie number years ago ... Ans comes to 45 years.

Now 85-45 = 40 years.

Is it correct way of solving ?

Gopalkrishna said:   1 decade ago
Present age:

H+W+C=30*3.
W+C=25*2.
....................
ie...,H=40 year.

ALIYAZ said:   1 decade ago
@PRIYA.

[(h-3)+(w-3)+(c-3)/3] = 27.
[(h+w+c-9)/3] = 27.
[(h+w+c)/3]+(9/3) = 27.
[(h+w+c)/3] = 27+3 ====>h+w+c=30*3 ====>h+w+c=90.
Similarly w+c = 50.

Kholofelo said:   1 decade ago
What is algorithm?

Vijaykumar said:   1 decade ago
Good method to solve such type of question.

Raj said:   1 decade ago
No need to add 3 to all.

You have add 3 to avg it give avg age of all.

Then age of three number = 30*3 = 90.

Then add 5 to avg age of child and wife it gives present age i.e. 25.

Age of two persons = 25*2 = 50.

Age of husband = total age - two members age.

90 - 50 = 40.

Ritu Sehgal said:   1 decade ago
Let husband present age - x.
Let wife present age - y.
Let son present age - z.

The average age of husband, wife and son before 3 years was 27.

i.e Before 3 year (x-3)+(y-3)+(z-3)/3 = 27.

x-3+y-3+z-3 = 27*3.
x+y+z = 81+9.
x+y+z = 90.....(1).

The average age of wife and son before 5 years was 20.

i.e Before 5 years (y-5)+(z-5)/2 = 20.

y-5+z-5 = 20*2.
y+z = 40+10.
y+z = 50....(2).

Now by subtracting equation 2 from equation 1, we will find x = 40.

Kesava said:   10 years ago
1. Before 3 years husband+wife+child = 27.

Now = 30*3 = 90.

2. Before 5 years wife+child = 20.

Now = 25*2 = 50.

Husband age = 90-50 = 40.

Naseem Saifi said:   10 years ago
Let age of husband, wife and child is x, y, z.

Then 3 year ago age of husband, wife and child was x-3, y-3, z-z.

Given that 3 year ago average of their age was 27.

So (x-3+y-3+z-3) /3 = 27.

=> x+y+z-9 = 81.

=> x+y+z = 90____ (1).

5 year ago age of wife and child was y-5 and z-5.

Given that 5 year ago average of their age was 20.

So (y-5+z-5)/2 = 20.

=> y+z-10 = 40.

=> y+z = 50_______ (2).

Now, (1) - (2).

=> x = 40.

So age of husband is 40.

Guhan said:   9 years ago
Ramya it is very easy to understand. Keep solving the problem in the easiest way.


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