Aptitude - Average - Discussion
Discussion Forum : Average - General Questions (Q.No. 8)
8.
The average age of husband, wife and their child 3 years ago was 27 years and that of wife and the child 5 years ago was 20 years. The present age of the husband is:
Answer: Option
Explanation:
Sum of the present ages of husband, wife and child = (27 x 3 + 3 x 3) years = 90 years.
Sum of the present ages of wife and child = (20 x 2 + 5 x 2) years = 50 years.
Husband's present age = (90 - 50) years = 40 years.
Discussion:
101 comments Page 3 of 11.
YESU BABU PAGIDIMALLA said:
1 decade ago
Average of present ages of h,w,c=27+3=30
Average of present ages of w,c =20+5=25
so age of husband = 90-50=40
Average of present ages of w,c =20+5=25
so age of husband = 90-50=40
Karthy said:
1 decade ago
When the solution is started like this
husband=x,wife=y&child=z
bf4 3yrs x-3+y-3+z-3/3 =27
terefore x+y+z=90--1
bf4 5yrs y-5+z-5/2 =20
terefore y+z=50---2 (1-2)
terefore x=40
husband=x,wife=y&child=z
bf4 3yrs x-3+y-3+z-3/3 =27
terefore x+y+z=90--1
bf4 5yrs y-5+z-5/2 =20
terefore y+z=50---2 (1-2)
terefore x=40
Vasavi said:
1 decade ago
Ramya your way of answering this was very good.
Srinivas said:
1 decade ago
husband+wife+child =3 years ago =27 present age =30 (27+3=30)
wife and child = 5 years ago =20 present age=25 (20+5=25)
h+w+c =3*30=90 -- I
w+c =2*25=50 --II
substract(I-II) 90-50=40 year
wife and child = 5 years ago =20 present age=25 (20+5=25)
h+w+c =3*30=90 -- I
w+c =2*25=50 --II
substract(I-II) 90-50=40 year
Rahul said:
1 decade ago
thanks ramya
Ashwin said:
1 decade ago
H+W+C=81 is sum three year ago and W+C=40 five year ago. So five year ago it is wife and child sum is 40. Each year a 1 age will be added for a person. So W+C=44 after two years. (now W+C=44 is three year ago) so H+44 = 81.
H = 37 three year ago. So at present his age is 37+3 = 40 = H.
H = 37 three year ago. So at present his age is 37+3 = 40 = H.
(1)
John Smith said:
1 decade ago
Present age of h+w+c = (27+3)*3 = 90.
Present age of w+c = (20+5)*2 = 50.
h's age = 90-50 = 40.
Present age of w+c = (20+5)*2 = 50.
h's age = 90-50 = 40.
(1)
Harpreet said:
1 decade ago
1. Av age of H+W+C=27.
Three years back their total age, we multiply 27 by 3 = 81 years.
Three years later age increased for three members = 3*3 = 9.
2. Current age of H+W+C = 90.
3. Av age of W+C = 20.
Five years back their total age, we multiply 20 by 2 = 40.
Five years later age increased for two members = 5*2 = 10.
4. Current age of W+C = 50.
5. Husband age = Current age of H+W+C-W+C = 90-50 = 40 years.
Three years back their total age, we multiply 27 by 3 = 81 years.
Three years later age increased for three members = 3*3 = 9.
2. Current age of H+W+C = 90.
3. Av age of W+C = 20.
Five years back their total age, we multiply 20 by 2 = 40.
Five years later age increased for two members = 5*2 = 10.
4. Current age of W+C = 50.
5. Husband age = Current age of H+W+C-W+C = 90-50 = 40 years.
(1)
Mahesh said:
1 decade ago
h+w+c/3 = 27.
h+w+c = 81.
w+c/2 = 20.
w+c = 40.
h+w+c = 81.
h+40 = 81.
h = 81-40.
h = 40.
h+w+c = 81.
w+c/2 = 20.
w+c = 40.
h+w+c = 81.
h+40 = 81.
h = 81-40.
h = 40.
Murali said:
1 decade ago
Given that average age of husband, wife, child 3 years ago was 27 years
average age of wife child 5 years ago was 20 years.
h+w+c/3 = 27.
h+w+c = 81 it is 3 years ago this is eq1.
w+c = 40 it is 5 years ago then it is convert in to 3 years ago i.e adding 2*2 = 4 therefore w+c=44 eq2.
Eq1-eq2 we get h=37 this is 3 years age so add 3 years to get present age
answer is 40 years.
average age of wife child 5 years ago was 20 years.
h+w+c/3 = 27.
h+w+c = 81 it is 3 years ago this is eq1.
w+c = 40 it is 5 years ago then it is convert in to 3 years ago i.e adding 2*2 = 4 therefore w+c=44 eq2.
Eq1-eq2 we get h=37 this is 3 years age so add 3 years to get present age
answer is 40 years.
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