Aptitude - Average - Discussion
Discussion Forum : Average - General Questions (Q.No. 8)
8.
The average age of husband, wife and their child 3 years ago was 27 years and that of wife and the child 5 years ago was 20 years. The present age of the husband is:
Answer: Option
Explanation:
Sum of the present ages of husband, wife and child = (27 x 3 + 3 x 3) years = 90 years.
Sum of the present ages of wife and child = (20 x 2 + 5 x 2) years = 50 years.
Husband's present age = (90 - 50) years = 40 years.
Discussion:
104 comments Page 3 of 11.
Ks Venkatesh said:
1 decade ago
Its simple:
Avg of 6 family members before 10 years is (Hus-10)+(wife-10)+(fath-10)+(othrs-30)/6 at 10 years ago.. By simpllifing abv we get (hus+wife+fath+othrs-60)/6
Present age average(Here babe replaces father): (Hus+wif+Babe+others)/6
As per given condition equate both the abv equ: U'll get Father's age=60 years..!! QUITE EASY NA ??
Avg of 6 family members before 10 years is (Hus-10)+(wife-10)+(fath-10)+(othrs-30)/6 at 10 years ago.. By simpllifing abv we get (hus+wife+fath+othrs-60)/6
Present age average(Here babe replaces father): (Hus+wif+Babe+others)/6
As per given condition equate both the abv equ: U'll get Father's age=60 years..!! QUITE EASY NA ??
Sayed Sirajunnisa said:
6 years ago
A family of six members bought a car 10 years ago, and had a road accident today, in which one of the family members died. The average age of the family at the time when they bought the car is same as of today. What was the age of the member who passed away?can anyone help me with this problem, I need solution to this Question.
(1)
Abu Kipa said:
2 years ago
Present age average of H+W+C,
(H+W+C)/3 =30 ,since 27 + after 3 years.
=> H+W+C= 90(equation 1)
Present age average of Wife and Child,
(W+C)/2= 25(since 20+ 5 additional years),
=> W+C= 50(equation 2).
Substitution of W+C = 50 in equation 1 gives, H+W+C= 90,
=> H+50= 90 (since W+C= 50).
=> H= 40 years.
(H+W+C)/3 =30 ,since 27 + after 3 years.
=> H+W+C= 90(equation 1)
Present age average of Wife and Child,
(W+C)/2= 25(since 20+ 5 additional years),
=> W+C= 50(equation 2).
Substitution of W+C = 50 in equation 1 gives, H+W+C= 90,
=> H+50= 90 (since W+C= 50).
=> H= 40 years.
(52)
RENU said:
2 decades ago
Question: When I was married 10 years ago my wife is the 6th member of the family. Today my father died and a baby born to me.The average age of my family during my marriage is same as today. What is the age of Father when he died?
Can anyone help me to find solution for this question AS SOON AS POSSIBLE?
Can anyone help me to find solution for this question AS SOON AS POSSIBLE?
Ashwin said:
1 decade ago
H+W+C=81 is sum three year ago and W+C=40 five year ago. So five year ago it is wife and child sum is 40. Each year a 1 age will be added for a person. So W+C=44 after two years. (now W+C=44 is three year ago) so H+44 = 81.
H = 37 three year ago. So at present his age is 37+3 = 40 = H.
H = 37 three year ago. So at present his age is 37+3 = 40 = H.
(1)
Shubhanshu said:
2 years ago
3 years ago, the average age of H+W+C was 27.
The present average age of H+W+C /3 = 30 (each age increment by 3 so 3+3+3/3 =3)
5 years ago, the average age of w+c/2 = 20.
present average age will be w+c/2 = 25.
The present age of the husband will be h+w+c - (w+c) = 90 - 50 = 40.
The present average age of H+W+C /3 = 30 (each age increment by 3 so 3+3+3/3 =3)
5 years ago, the average age of w+c/2 = 20.
present average age will be w+c/2 = 25.
The present age of the husband will be h+w+c - (w+c) = 90 - 50 = 40.
(39)
Ahir n.m said:
8 years ago
The average age of a husband and wife at the time of their marriage was 25 years. A son was born to them exactly 2 years after their marriage and the average present age of all three is 24 years. How many years have been passed by the couple?
Can anyone explain the answer of this?
Can anyone explain the answer of this?
SRIRAM said:
7 years ago
@All.
Take x, y, z intial age is 27 after three years it converted into 30. For three members it is 90.
Then 5 years back 20 years. Calculate with present age it is 25.
Now
X+Y+Z=(3*30)=90.
Y+Z=20(5 years back)Now =(25*2)=50,
Now equate it.
Y+Z cancelled,
X=90-50.
And X=40.
Take x, y, z intial age is 27 after three years it converted into 30. For three members it is 90.
Then 5 years back 20 years. Calculate with present age it is 25.
Now
X+Y+Z=(3*30)=90.
Y+Z=20(5 years back)Now =(25*2)=50,
Now equate it.
Y+Z cancelled,
X=90-50.
And X=40.
Shasi kumar said:
6 years ago
Five years ago, the average age of the Ram family has 5 members including Ram was 29 years. Ram got married 3 years ago and his only child was born 2 years after marriage so that the present average age of family becomes 28 years. Find the age of a bride at the time of marriage?
(2)
Raj said:
1 decade ago
No need to add 3 to all.
You have add 3 to avg it give avg age of all.
Then age of three number = 30*3 = 90.
Then add 5 to avg age of child and wife it gives present age i.e. 25.
Age of two persons = 25*2 = 50.
Age of husband = total age - two members age.
90 - 50 = 40.
You have add 3 to avg it give avg age of all.
Then age of three number = 30*3 = 90.
Then add 5 to avg age of child and wife it gives present age i.e. 25.
Age of two persons = 25*2 = 50.
Age of husband = total age - two members age.
90 - 50 = 40.
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